How to replace the diagonal elements of a matrix with 0 fro avoiding self loops?

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SUNANNA S S
SUNANNA S S 2017-4-19
评论： tommsch 2024-6-28
I have a matrix
M= 1 0 0 0 1 0
0 1 0 1 0 0
0 0 1 0 1 1
1 0 0 1 0 0
1 1 1 0 0 0
0 0 0 1 0 1
I want to replace all the diagonal elements in this matrix to 0 if it is 1.
  1 个评论
Ramtin Nazerian
Ramtin Nazerian 2022-12-21
Out = M.*-(eye(height(M))-1);
This will make all the diagonal values of your matrix zero as long as the matrix is square. hope that helps :).

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2017-5-23
out = M - diag(diag(M));

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Stephen23
Stephen23 2017-4-19
编辑：Stephen23 2017-4-19
Method one: indexing:
M(1:1+size(M,1):end) = 0
Method two: eye:
M.*~eye(size(M))
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Stephen23
Stephen23 2017-4-19
A strict interpretation of the question requires only diagonals equal to one get changed to zero: this is easy to implement with eye:
M.*~(eye(size(M)) & M==1)

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Roger Stafford
Roger Stafford 2017-4-19
If your matrix M is not square and if you only want those diagonal elements changed to zero “if it is 1”, then you can do the following. Other diagonal elements not equal to one will remain unchanged. (Your description was perhaps a little ambiguous on this latter point.)
[m,n] = size(M);
d = 1:m+1:min(m^2,m*(n-1)+m);
f = find(M(d))==1;
M(d(f)) = 0;
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Christine Tobler
Christine Tobler 2017-5-23
编辑：Christine Tobler 2017-5-23
If you are using the graph/digraph classes, you can also tell the constructor not to insert any self-loops for the diagonal elements:
g = graph(A, 'omitSelfLoops');

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