What does \\\r\n mean ?

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Ronny Landsverk
Ronny Landsverk 2017-4-25
Using symbolic variables in matrix-multiplication with elements consisting of trig-functions I came across a symbol that I have not seen before. It shows up in two elements in the result:
38769523591\\\r\n65965*Dq3*sin(2*q2 + q3)
and
-\\\r\n 1578177954729427/1073741824
What is this mysterious operator ? I tried using vpa(), but still the operator got promped. However, using
vpa(ans,2)
the operator disappeared. I guess it has something to do with numerical accuracy in the symbolic math engine...
  6 个评论
Jan
Jan 2017-4-25
Does it shed any light to your problem that \r\n is the standard DOS line break?
Ronny Landsverk
Ronny Landsverk 2017-4-25
Hi Jan Simon. Yes it does. However, I think this is a bug since these show up as part of an answer prompted by MATLAB... Do you have a comment ?

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采纳的回答

Jan
Jan 2017-4-25
In format specificators e.g. in sprintf the backslash is used as escape character: the following character get a special meaning: \r is a "carriage return" and \n a "new line". Both together are used by DOS applications as line break. To get a backslash charater, \\ is used.
Remark: You can ask an internet search engine for "\r \n" also. I like this forum very much, but e.g. Google finds an answer in less than a second.
  3 个评论
ali
ali 2017-12-17
I have a same problem, how to use new line???
Walter Roberson
Walter Roberson 2017-12-17
strrep(TheOutput, '\\\r\n', '')
Note that in cases where you get these characters, it would not be uncommon to see a message about truncated output. To view the whole output, see the work-around I gave in the link in my answer.

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更多回答(2 个)

Walter Roberson
Walter Roberson 2017-4-26
It is a bug in the output of long symbolic expressions. I submitted a report about it a few months ago. It would not hurt to submit a report yourself, so that they know I am not the only person affected.

Mohamed Abdelhamid
I did encounter that "\\\r\n" in some really long symbolic expressions. All I did was use find/replace to replace it with nothing. It did work pretty nice after that and the calculations were indeed correct.

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