The problem about dir function
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hi every one:
when I use dir function to get the same type files of a file, (the file name is 10.png, 20.png, 50.png, 100.png, 200.png, 300.png, 1000.png), then I find the sequence is 10.png, 100.png, 1000.png, 20.png, 200.png.....
but what I want to get is the sequence like 10.png, 20.png, 50.png, 100.png, 200.png, 300.png, 1000.png
so please give me some suggestion or any help
thanks a lot
1 个评论
>> S = dir('*.txt');
>> S.name
ans =
'1.txt'
ans =
'10.txt'
ans =
'2.txt'
>> S = natsortfiles(S); % alphanumeric sort by filename
>> S.name
ans =
'1.txt'
ans =
'2.txt'
ans =
'10.txt'
采纳的回答
Jan
2012-3-28
The most practical method is to use "0010" instead of "10". Then the numerical order equals the lexicographical order.
While there are some FEX submissions for "natural sorting", you can sort the names manually also:
List = dir('*.png');
Name = {List.name};
S = sprintf('%s,', Name{:}); % '10.png,100.png,1000.png,20.png, ...'
D = sscanf(S, '%d.png,'); % [10; 100, 1000; 20; ...]
[sortedD, sortIndex] = sort(D); % Sort numerically
sortedName = Name(sortIndex); % Apply sorting index to original names
更多回答（1 个）
David Young
2012-3-28
You could do something like this:
dstruct = dir('*.png');
names = {dstruct.name};
maxlen = max(cellfun(@length, names));
padname = @(s) sprintf(['%0' num2str(maxlen) 's'], s);
namesPadded = cellfun(padname, names, 'UniformOutput', false);
[~, sortOrder] = sort(namesPadded);
dstruct = dstruct(sortOrder);
The structure is now in the order you want. To see this, you can execute
disp({dstruct.name})
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