I can not create a matrix

2017 4 26
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更新时间：2017 5 5
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DNdog =
7
11
BNdog =
4
4
blnmynokta =
11
for i = 1:length(DNdog)
for j = 1:(length(blnmynokta))
if (BNdog(i) == blnmynokta(j))
A(i,j) = [1];
elseif (DNdog(i) == blnmynokta(j))
A(i,j) = [-1];
end
end
end
A =
0
-1 % This matrix is formed.
The matrix that should occur is;

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Jan
Jan 2017-4-26
What exactly is your question?
Muhendisleksi
Muhendisleksi 2017-4-26
A =
0 0 0
0 0 0
0 0 0
-1 0 0
0 -1 0
0 0 -1
I have to get this result. But I could not.

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 采纳的回答

Stephen23
Stephen23 2017-4-26
编辑：Stephen23 2017-4-26

0 个投票

This is simple with toeplitz:
>> nC = 3;
>> nR = 6;
>> vC = zeros(1,nC);
>> vR = zeros(1,nR);
>> vR(end-nC+1) = -1;
>> toeplitz(vR,vC)
ans =
0 0 0
0 0 0
0 0 0
-1 0 0
0 -1 0
0 0 -1

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Andrei Bobrov
Andrei Bobrov 2017-4-26
A = zeros(nR,nC);
A(nC+1:nR+1:end) = -1;
Muhendisleksi
Muhendisleksi 2017-5-5
nC = 6;
nR = 6;
If nC and nR take these values;
A =
0 0 0 0 0 0
0 0 0 0 0 0
0 0 0 0 0 0
-1 0 0 1 0 0
0 -1 0 0 1 0
0 0 -1 0 0 1 %How can I get this value?
Stephen23
Stephen23 2017-5-5
@Muhendisleksi: you can solve this yourself quite easily. One way would be to use zeros and toeplitz and concatenate the outputs on top of each other. When you actually read the documentation and try some examples then you will learn how to use MATLAB and you will learn how to solve problems yourself. Start by reading the docs for the two functions that I told you, and experimenting with them.
https://www.mathworks.com/matlabcentral/answers/228557-experts-of-matlab-how-did-you-learn-any-advice-for-beginner-intermediate-users

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