Checking if an array element is larger than the following elements

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So if I have a large array of form A=[1,5,6,4,12...], is there a consistent way of checking if some element A(n), let's say A(3), is larger than the following ones? So in this case, I would like to find out that A(3)>A(4). Also, then I would like to change those elements in a way that any element A(n) is always equal or larger than any of the elements before it. So again, in this case I would like to change my array A from [1,5,6,4,12...] -> [1,4,4,4,12...] or [1, NaN, NaN,4,12,...].
Thank you.
  3 个评论
Valtteri Tikkanen
Valtteri Tikkanen 2017-5-11
编辑:Valtteri Tikkanen 2017-5-11
I have tried this:
A=[1,5,6,4,12,14,13];
for i=2:7
if gt(A(i-1),A(i))
A(i-1)=A(i)
end
end
Which produces A=[1,5,4,4,12,13,13]. The problem is that I do not know how reach elements further away, so for example A(2) is not corrected.

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采纳的回答

Jan
Jan 2017-5-11
编辑:Jan 2017-5-11
This is not hard. Please feel encouraged to try it by your onw.
A = [1,5,6,4,12];
X = A(length(A));
for k = length(A)-1:-1:1
if A(k) > X
A(k) = X; % Or: NaN
else
X = A(k);
end
end

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