Write a function called integerize that takes as its input a matrix A of integers of type double, and returns the name of the “smallest” signed integer class to which A can be converted without loss of information. If no such class exists, the text '

4 次查看（过去 30 天）
Wasi von Deutschland
编辑： Stephen23 2018-8-25
function integerize(A)
int8(A<2^7-1);
int16(A<2^15-1);
int32(A< 2^31-1);
int64(A<2^63-1);
end
  3 个评论
显示 1更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Stephen23
Stephen23 2017-5-26
编辑：Stephen23 2018-5-29
EDIT: see Guillermo Varela Carbajal's answer below for a really neat solution.
Try something like this:
function typ = integerize(A)
if A >= intmin('int8') & A <= intmax('int8')
typ = 'int8';
elseif A >= intmin('int16') & A <= intmax('int16')
typ = 'int16';
elseif A >= intmin('int32') & A <= intmax('int32')
typ = 'int32';
elseif A >= intmin('int64') & A <= intmax('int64')
typ = 'int64';
else
typ = 'NONE';
end
end
and tested:
>> integerize([128,127;-127,0])
ans = int16
Just for the sake of discussion, here is a function where the list of accepted classes are specified as an input argument (as long as the order from smallest to largest is kept):
function typ = integerize(A,C)
for k = 1:numel(C)
typ = C{k};
if A >= intmin(typ) & A <= intmax(typ)
return
end
end
typ = 'NONE';
end
and tested:
>> integerize(A,{'int8','int16','int32','int64'})
ans = int16
>> integerize(A,{'int8','int32','int64'})
ans = int32
>> integerize(A,{'int8','int64'})
ans = int64
>> integerize(A,{'int8'})
ans = NONE

更多回答（5 个）

Guillermo Varela Carbajal
Trying to keep it simple, what about this:
function out = integerize (A)
if A==int8(A)
out='int8';
elseif A==int16(A)
out='int16';
elseif A==int32(A)
out='int32';
elseif A==int64(A)
out='int64';
else
out='NONE';
end
Jan
Jan 2017-5-26
编辑：Jan 2017-5-26
Get the largest elemt at first:
maxA = max(A(:));
Then use the logarithm to the base of 2 to determine the number of bits, which are required.
Finally some IF command let you create the output string 'int8', 'int16', 'int32' or 'int64'.
  13 个评论
显示 11更早的评论
Jan
Jan 2017-5-26
编辑：Jan 2017-5-26
@Wasi: Do you see the problem? You check for < 127, but -129 is smaller than 127 also. Add this:
minA = min(A(:));
if maxA <= 127 && minA >= -128
Another hint to simplify the code:
if maxA<=2^7-1;
x='int8';
elseif maxA <= 2^15-1 % This is not needed: && maxA>2^7-1
The case maxA <= 127 has been excluded before, then you do not have to check for > 127 anymore.

请先登录，再进行评论。

Jorge Briceño
Jorge Briceño 2018-2-9
Hi,
Another answer would be like this:
function [ smallA ] = integerize( A )
minimum = min(A(:));
maximum = max(A(:));
if minimum >= -2^7 && maximum<=2^7-1
smallA='int8';
elseif minimum >=-2^15 && maximum<=2^15-1
smallA='int16';
elseif minimum >=-2^31 && maximum<=2^31-1
smallA='int32';
elseif minimum >=-2^63 && maximum<=2^63-1
smallA='int64';
else
smallA='NONE';
end
Erfan Pakdamanian
Erfan Pakdamanian 2018-5-28
编辑：Erfan Pakdamanian 2018-5-28
My algorithm may seem to have a little bit more lines than Stephen but it does pretty much the same thing with basic functions
function s=integerize(A)
[ii,jj]=size(A);
y1=0;y2=0;y3=0; y4=0;
for ii=1:ii
for jj=1:jj
if A(ii,jj)>= -128 && A(ii,jj)<= 127
end y1=y1+1;
elseif (A(ii,jj) <= -129 && A(ii,jj)>127) || (A(ii,jj)>= -32768 && A(ii,jj)<=32767)
y2=y2+1;
elseif (A(ii,jj) <-3276 && A(ii,jj)>32767) || (A(ii,jj)>= -(2)^31 && A(ii,jj)< 2^31)
y3=y3+1;
elseif (A(ii,jj) < -(2)^31 && A(ii,jj)>= 2^31) || (A(ii,jj)>= -(2)^63 && A(ii,jj)<= 2^63)
y4=y4+1;
else
s='NONE';
return;
end
end
end
if y4>0
s='int64';
elseif y4==0 && y3>0
s='int32';
elseif y4==0 && y3==0 && y2>0
s='int16';
else
s='int8';
end
end
Gurleen Singh
Gurleen Singh 2018-8-25
This is a bit simpler(but longer) code.
function c = integerize(A)
m = max(A(:));
n = min(A(:));
if n>=-128 && m<= 127
m = int8(m);
n = int8(n);
c = class(m);
c = class(n);
elseif n>=-2^15 && m<=2^15-1
m = int16(m);
n = int16(n);
c = class(m);
c = class(n);
elseif n>=-2^31 && m<=2^31-1
m = int32(m);
n = int32(n);
c = class(m);
c = class(n);
elseif n>=-2^63 && m<=2^63-1
m = int64(m);
n = int64(n);
c = class(m);
c = class(n);
else
c = 'NONE';
end
  2 个评论
Walter Roberson
Walter Roberson 2018-8-25
Why are you writing to c twice for each case?
Why are you bothering to convert m and n to an explicit data type and then take class() of that data? Why not just assign 'int8' or whatever directly?
Stephen23
Stephen23 2018-8-25
编辑：Stephen23 2018-8-25
Why call class twice within each if / elseif block, and yet throw away the answer for the first call?
If you already know the class (which you do, because you have explicitly written uint8, int16, etc.), then why call those four lines within each block? E.g. rather than this:
m = int8(m); % <- look, you already use INT8!
n = int8(n);
c = class(m);
c = class(n);
you just need
c = 'int8'; % so why not just write 'INT8' ?

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by