Problem with "Intersect" function
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Hellow everyone! I have 2 cells.
A = '1,2,3';
B= '1,4,5,6';
But, When i try to use intersect function to get the common element(s) as my result, say
C = intersect(A, B);
I am getting an empty cell like this.
C =
Empty cell array: 1-by-0
Kindly help me, My result shall show like
C='1'
Your help will be highly appreciated!
4 个评论
alice
2017-6-22
Hi,
I think your A and B are:
A = {'1,2,3'};
B = {'1,4,5,6'};
This means A is a cell containing the string '1,2,3' and B is a cell containing the string '1,4,5,6'. These strings are different, so the intersection of A and B is empty.
To get what you want, the numbers should be separated (different strings, or just numbers).
How are A and B defined in your code?
Stephen23
2017-6-22
"Problem with "Intersect" function"
There is no problem with intersect: you have given it two cell arrays containing different strings, so clearly the intersection is an empty cell array. This is exactly as the documentation states.
pradeep kumar
2017-6-22
pradeep kumar
2017-6-22
采纳的回答
But the shown code works:
A = '1,2,3';
B = '1,4,5,6';
C = intersect(A, B);
% C = ',1' % The commonly appearing characters ',' and '1'
According to the posted code, A and B are not cells, but char vectors, also called strings.
If you want to treat the numbers as numbers:
An = sscanf(A, '%g,');
Bn = sscanf(B, '%g,');
Cn = intersect(An, Bn)
% C = 1
If A and B are cells, use "A{1}" and "B{1}" instead.
It depends on your specific problem if the input data should be
A = {'1','2','3'};
or
A = [1,2,3]
Most likely you do not have to convert the cell string {'1,2,3'}, if you choose the rigth method to obtain the data at the beginning. Where do these data come from?
更多回答（1 个）
KSSV
2017-6-22
A = [1,2,3] ;
B = [1,4,5,6];
intersect(A,B)
OR
A = '1,2,3';
B= '1,4,5,6';
intersect(str2num(A),str2num(B))
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