Problem with "Intersect" function

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pradeep kumar
pradeep kumar 2017-6-22
编辑： Jan 2017-6-22
Hellow everyone! I have 2 cells.
A = '1,2,3';
B= '1,4,5,6';
But, When i try to use intersect function to get the common element(s) as my result, say
C = intersect(A, B);
I am getting an empty cell like this.
C =
Empty cell array: 1-by-0
Kindly help me, My result shall show like
C='1'
Your help will be highly appreciated!
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pradeep kumar
pradeep kumar 2017-6-22
@ Alice! Yes, A & B are different cells and contain strings. Please tell me how can i break them to individual number (or strings) to get my job done.
pradeep kumar
pradeep kumar 2017-6-22
@ Stephen Cobeldick , You mean to say my cells should look like the following .
A={'1','2','3'};
B={'1','4','5','6'};
Kindly tell me, how can i achieve this?

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采纳的回答

Jan
Jan 2017-6-22
编辑：Jan 2017-6-22
But the shown code works:
A = '1,2,3';
B = '1,4,5,6';
C = intersect(A, B);
% C = ',1' % The commonly appearing characters ',' and '1'
According to the posted code, A and B are not cells, but char vectors, also called strings.
If you want to treat the numbers as numbers:
An = sscanf(A, '%g,');
Bn = sscanf(B, '%g,');
Cn = intersect(An, Bn)
% C = 1
If A and B are cells, use "A{1}" and "B{1}" instead.
It depends on your specific problem if the input data should be
A = {'1','2','3'};
or
A = [1,2,3]
Most likely you do not have to convert the cell string {'1,2,3'}, if you choose the rigth method to obtain the data at the beginning. Where do these data come from?

更多回答（1 个）

KSSV
KSSV 2017-6-22
A = [1,2,3] ;
B = [1,4,5,6];
intersect(A,B)
OR
A = '1,2,3';
B= '1,4,5,6';
intersect(str2num(A),str2num(B))
  1 个评论
pradeep kumar
pradeep kumar 2017-6-22
@ KSSV, str2num doesn't work, since A and B are 2 cells. It shows the following error.
Error using str2num (line 32)
Requires string or character array input.
Kindly help me.

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