How to assign a matrix instead of scalar in another matrix at specified locations with or without kronecker product?

Question

Udit Srivastava 2017-7-6

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/347623-how-to-assign-a-matrix-instead-of-scalar-in-another-matrix-at-specified-locations-with-or-without-kr

评论： Guillaume 2017-7-6

Hello all,

I have a tri-diagonal matrix F (n-by-n) and a diagonal matrix G(n-by-n). Now, I want to construct a matrix A(n^2-by-n^2) (with kronecker product or without it) with matrix F lying on main diagonal of A (A becomes a tri-diagonal matrix after this step) and putting G on the 2 adjacent diagonals (A becomes a penta-diagonal matrix after this step).

Any thoughts about how this could be done?

Thank you.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Guillaume 2017-7-6

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/347623-how-to-assign-a-matrix-instead-of-scalar-in-another-matrix-at-specified-locations-with-or-without-kr#answer_273121

编辑：Guillaume 2017-7-6

在 MATLAB Online 中打开

There may be something in gallery, otherwise this would work:

elems = {F, G, zeros(size(F))};
result = cell2mat(elems(min(toeplitz(1:size(F, 1)), 3)))

2 个评论
显示无隐藏无

Udit Srivastava 2017-7-6

works good but I have a small doubt. How is that '3' (in 2nd line) helping?

Guillaume 2017-7-6

在 MATLAB Online 中打开

The whole idea is to generate an indexing matrix that chooses between F, G, and the zeros. Therefore you only want indices between 1 and 3. My min(toeplitz(1:size(F, 1)), 3) is just one way of generating that indexing matrix. Other possibilities:

toeplitz(min(1:size(F, 1), 3))
toeplitz([1:3, repmat(3, size(F, 1)-2, 1))
gallery('tridiag', size(F, 1), 1, 2, 1) + 1  %with this one you have to change the order in elems to {0, G, F}

请先登录，再进行评论。