0 个投票

hi,
i want to write the following equation in a for loop to store values for 1000 rows..Can anyone help please?
z(k)=lamda*x(k)+(1-lamda)*z(k-1)

请先登录，再回答此问题。

 采纳的回答

Jan
Jan 2017-7-8

0 个投票

z = zeros(1000, 22);
x = rand(1000, 22);
lamda = rand();
for k = 2 : 1000
z(k, :) = lamda * x(k, :) + (1-lamda) * z(k-1, :);
end

4 个评论
显示 2更早的评论 隐藏 2更早的评论

Md. Tanjin Amin
Md. Tanjin Amin 2017-7-8
Hi, the code runs ..still the result is not satisfactory....I am attaching the data file and expected result for lamda=0.03. I have done the calculation using excell. Can you look again and help please? Thank you.
Walter Roberson
Walter Roberson 2017-7-8
Your expected values are wrong, not even self-consistent.
See attached code and plots.
Md. Tanjin Amin
Md. Tanjin Amin 2017-7-10
Hi, I am sorry. You are right the expected values were wrong. I have attached the corrected expected values. This is right this time. Can you give some time and help please?
Walter Roberson
Walter Roberson 2017-7-10
Your first two lines of X from X.mat are the same. That cannot be explained with any lamda other than 0 .
Your other lines of expected output cannot be explained with lamda = 0.03 : they all require lamda = 1.0003
Even then your expected outputs are frequently wrong in the 4th digit.
See attached, which is configured for 1.0003

请先登录，再进行评论。

更多回答（1 个）

Walter Roberson
Walter Roberson 2017-7-8

0 个投票

z(1) = rand();
x = randn(1,1000);
lamda = rand();
for k = 2 : 1000
z(k)=lamda*x(k)+(1-lamda)*z(k-1);
end

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

Md. Tanjin Amin
Md. Tanjin Amin 2017-7-8
Hi, Thank you. Atually, I should have been more specific. X is 1000*22 matrix and initial value of Z is zero (a 1*22 zero matrix)..Can you help please?

请先登录，再进行评论。

类别

在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by