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find element in cell

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skysky2000
skysky2000 2017-7-12
评论： dbmn 2017-7-13
Dear all, I've problem with the cell,
a= {[67 8 33] [1 2 3 5] [2 88 5] [3 66 7 90] [3] [66 78 12 1 44 6 77 3]},
how to find each cell have number 3. answer expect it is:
b= {[1 2 3 5] [3 66 7 90] [3] [66 78 12 1 44 6 77 3]}
thanks all

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回答（2 个）

dbmn
dbmn 2017-7-12
An alternative to KSSVs solution would be this one liner
b = a(cellfun(@(x) sum(x==3)>0, a));
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Jan
Jan 2017-7-12
The result of sum(x==3)>0 is unclear, when the cell element is the empty matrix. What about:
b = a(cellfun(@(x) any(x==3), a));
dbmn
dbmn 2017-7-13
Nice, using "any" there is a really neat idea.

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KSSV
KSSV 2017-7-12
a= {[67 8 33] [1 2 3 5] [2 88 5] [3 66 7 90] [3] [66 78 12 1 44 6 77 3]} ;
b= {[1 2 3 5] [3 66 7 90] [3] [66 78 12 1 44 6 77 3]} ;
iwant = cell([],1) ;
count = 0 ;
for i = 1:length(a)
if any(a{i}==3)
count = count+1 ;
iwant{count} = a{i} ;
end
end
iwant

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