distance

2012 4 11
1 个回答
2 次查看（30 天）

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Hi, I'm trying to find middle distance. We did it this way
c1=handles.centroids(:,1);
c2=handles.centroids(:,2);
d1=sqrt(((xi(:,1)-c1))^2+(yi(:,1)-c2)^2);
d11=sqrt(((xi(:,2)-c1))^2+(yi(:,2)-c2)^2);
vz1=(d1+d11)/2;
str = ['strední vzdalenost v prvním okně je ', num2str(d1), ' pixelu.'];
disp (str);
but my voice is a mistake vcem Does anybody know the problem?
??? Error using ==> mpower
Inputs must be a scalar and a square matrix.
Thank you very much

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回答（1 个）

Andrei Bobrov
Andrei Bobrov 2012-4-11

1 个投票

use .^
d1=sqrt(((xi(:,1)-c1))^2+(yi(:,1)-c2)^2);
d11=sqrt(((xi(:,2)-c1)).^2+(yi(:,2)-c2).^2);
on comment
d = sqrt((xi-c1).^2+(yi-c2).^2);
vz1 = mean(d);

5 个评论
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Adam
Adam 2012-4-11
after treatment system reports this error:
Attempted to access xi(:,2); index out of bounds because
size(xi)=[2,1].
Jan
Jan 2012-4-11
@Adam: The error message is clear: You try to access a not existing element of the array xi. Because you did not explain or show how xi is created, it is impossible to give any advice.
Adam
Adam 2012-4-11
ginput create using the values xi yi, which is also at the function as the rows to calculate the distance.
hold on
n=0;
[xi,yi,but] = ginput(2);
% plot(xi,yi,'g*');
n = n+1;
x(:,n) = xi;
y(:,n) = yi;
plot(xi,yi,'r*');
%xy(:,n) = [xi;yi];
hold off
Adam
Adam 2012-4-13
Well here is the complete code as I realized. When inserting one point so it works, for more no:
file_name ='bw.bmp';
BW = imread(file_name);
imshow (BW)
s3 = regionprops(BW, 'centroid');
centroids3 = cat(1, s3.Centroid);
hold on
plot(centroids3(:,1), centroids3(:,2), 'r*')
hold off
hold on
n=0;
[a,b,but] = ginput(2);
n = n+1;
x(:,n) = a;
y(:,n) = b;
plot(a,b,'r*');
hold off
c1=centroids3(:,1);
c2=centroids3(:,2);
d1=sqrt(((a-c1)).^2+(b-c2).^2);
d11=sqrt(((a-c1))^2+(b-c2).^2);
vz1=(d1+d11)/2;
str = ['strední vzdalenost v prvním okně je ', num2str(vz1), ' pixelu.'];
disp (str);
can be downloaded from the link picture:
http://www.ulozto.cz/xAEvHHw/bw-bmp
Adam
Adam 2012-4-13
I had the problem resolved but it is not very elegant solution ... I'll happy with any help.
thank you

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Adam
Adam
2012-4-11

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