Creating variables consisting of many elements

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Gratitude Kim
Gratitude Kim 2017-8-4
评论： Andrei Bobrov 2017-8-4
I want to create a variable consisting of X1 to X10 . Is there an easy way instead of typing X1 to X10?
V1={'X1','X2','X3','X4','X5','X6','X7','X8','X9','X10'}
Thanks
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Stephen23
Stephen23 2017-8-4
编辑：Stephen23 2017-8-4
@Gratitude Kim: what do you need these string for? The best solution may well depend on your usecase.
>> arrayfun(@(n)sprintf('X%d',n),1:10,'uni',0)
ans =
'X1'
'X2'
'X3'
'X4'
'X5'
'X6'
'X7'
'X8'
'X9'
'X10'
or perhaps
>> regexp(sprintf('X%d ',1:10),'\S+','match')
If you are planning on accessing variables with those names then DON'T. Read this to know why:
https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

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回答（3 个）

Daniel Burke
Daniel Burke 2017-8-4
From your question it looks like you want V1 to be a cell array of strings, ranging from 'X1' to 'X10', this code should do the trick if that is your goal:
V1 = cell(1,10)
for i = 1:10
V1{i} = ['X' num2str(i)]
end
Jan
Jan 2017-8-4
Or the undocumented function sprintfc:
sprintfc('X%d', 1:10)
Philip Borghesani
If you don't mind strings and have R2017a I like:
"x"+(1:10)
Or if you want a cell array or have 2016b:
cellstr(string('x')+(1:10))

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