Finding sum of large array based on row values

2017 8 11
1 个回答
回答已采纳
更新时间：2017 8 11
1 次查看（30 天）

0 个投票

Hello, I have a big matrix where the 1st column varies for the year (1993 to 2014), 2nd column is month, 3rd column is day, 4th is hour, fifth min, sixth second and the last column is value. The value of 4th column varies from 0 to 23 hr, making a full day.
1993 4 2 0 0 0 2,44
1993 4 2 0 15 0 2,34
1993 4 2 0 30 0 2,21
1993 4 2 0 45 0 2,14
1993 4 2 1 0 0 2,04
1993 4 2 1 15 0 1,98
1993 4 2 1 30 0 1,92
1993 4 2 1 45 0 1,87
1993 4 2 2 0 0 1,79
1993 4 2 2 15 0 1,75
1993 4 2 2 30 0 1,73
1993 4 2 2 45 0 1,73
1993 4 2 3 0 0 1,72
1993 4 2 3 15 0 1,73
1993 4 2 3 30 0 1,78
1993 4 2 3 45 0 1,77
......................................................
......................................................
......................................................
2014 12 31 21 0 0 3,82
2014 12 31 21 15 0 3,89
2014 12 31 21 30 0 3,88
2014 12 31 21 45 0 3,89
2014 12 31 22 0 0 3,90
2014 12 31 22 15 0 3,85
2014 12 31 22 30 0 3,81
2014 12 31 22 45 0 3,74
2014 12 31 23 0 0 3,66
2014 12 31 23 15 0 3,56
2014 12 31 23 30 0 3,45
2014 12 31 23 45 0 3,34
I have to group the similar 4th row element (which varies from 0 to 23) and find out mean of the last column. So, the desired output would be:
1993 4 2 0 0 0 2.28
1993 4 2 1 0 0 1.95
1993 4 2 2 0 0 1.75
1993 4 2 3 0 0 1.75
.....................................................
.....................................................
2014 12 31 21 0 0 3,87
2014 12 31 22 0 0 3.82
Any help on this?

请先登录，再回答此问题。

 采纳的回答

alice
alice 2017-8-11
编辑：alice 2017-8-11

0 个投票

Calling your matrix data:
[dateAndHour,~,index] = unique(data(:,1:4),'rows'); % find the hours present in the matrix and attribute each element of the matrix to one of these hours
hourlyMean = accumarray(index,data(:,7),[],@mean); % compute the hourly mean
output = [dateAndHour,zeros(size(dateAndHour,1),2),hourlyMean]; % build the output

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Resizing and Reshaping Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by