How to perform KNN regression
3 次查看(过去 30 天)
显示 更早的评论
Hi,
I have data as below:
X:
1
2
3
4
9
11
13
17
19
20
y:
0.1
0.3
0.4
0.65
1.5
2.5
2.7
2.9
3.2
3.6
I want to compute y values for at x values at 6.3, 15.5&21.5
1. for each value of x, I want to take 4 nearest points in my calculation and choose most reasonable one as the final y
2. In the second method, compare minkowski & chebychev distances and choose most reasonable one
Many thanks in advance,
2 个评论
Jan
2017-8-26
There is no "most reasonable" in maths. You want a valus for x=21.5, but the original data stop at x=20. There is an infinite number of possible ways to extrapolate. Without any further information like "the data follow a polynomial of order 3" it is not possible to prefer any method or even to measure the degree or reasonability. Perhaps a linear interpolation is fair, and the extrapolated values should be simply NaN.
回答(1 个)
Royi Avital
2017-8-26
At each point you want to calculate the value (x, y) find the K closest point (For x).
Then average them to create the new value.
0 个评论
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!