Vectorization

2012 4 15
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Dear Community,
Let say I have Matrix M. In Matrix M, each Column is feature of Image. Now what I want to get a binary matrix B by following way.
for given image feature i:
B(1,i) = M(1,i) >= M(2,i);
its mean for each image feature, each cell is compared to its next cell. I want to do it without loops for speed.

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Oleg Komarov
Oleg Komarov 2012-4-15
"Without loops for speed" is really not the right statement anymore.
Many times loops are much faster is correctly set up.

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Jan
Jan 2012-4-15

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B = (M(1:end-1, :) >= M(2:end, :));

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Jan
Jan 2012-4-15
It is worth to investigate the similarities and differences to Oleg's (faster) solution.
Aravin
Aravin 2012-4-18
Jan, Oleg worked on my small examples. I could find any dissimilarity. If you have in your mind then please share.
Thanks for your help too.

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