converting uint32 to cell
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after operating the command
c4 = transpose( [ arrayl{:,4} ] );
in a matrix , c4 returns a columns of numbers (for more, refer to http://www.mathworks.in/matlabcentral/answers/35528-reading-numbers-from-an-unknown-format)
but the output is in uint32 format and i need to get it converted to cell format , suggestions please
采纳的回答
Walter Roberson
2012-4-16
array1(:,4)
seems to be what you are describing.
更多回答（1 个）
Jan
2012-4-16
This:
[ arrayl{:,4} ]
converts the elements of the 4th column of the cell array1 explicitly to a vector. If you do not want this conversion, omit it:
c4 = transpose(arrayl(:,4));
Or if you want a {Nx1} cell, see Walter's suggestion.
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