Nested loop code to fill a 10x100 matrix
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Hi all,
I'm pretty stuck on this one; I want to fill a 10x100 matrix as: A =
[1 2 3 . . .100
101 102 103 .
201 202 203 .
. . .
. . .
901 . . . . 1000]
Since I want to make use of for loops, I've made the following code:
u=10;
v=100;
A=zeros(u,v);
for m=1:u;
for n=1:v;
A(m,n)= ....
end
end
I manage to get the first row going from 1 to 100, but I can't seem to get the second row (and so on) to start with A(1,1)+m*100. I can guess that the problem is in the first loop, but I just can't seem to solve it. Anyone here who can help me getting the right code for A(m,n)=....? Or am I doing it completely wrong in the first place?
Thank you!
1 个评论
James Tursa
2017-9-15
Do you have to use loops because this is a homework assignment?
采纳的回答
Jan
2017-9-15
0 个投票
You are almost there: All you have to do is to set the element to 100*(m-1) + n.
Sorry for solving your homework, if it is one. Note that your teacher knows this forum also. But you have shown your effort and asked clearly.
更多回答（2 个）
Andrei Bobrov
2017-9-15
编辑：Andrei Bobrov
2017-9-15
out = (1:100) + (0:100:900)'
for older version of MATLAB:
out = bsxfun(@plus,1:100,(0:100:900)')
1 个评论
Note: See this example https://www.mathworks.com/matlabcentral/answers/356103-euclidean-distance-ed-calculation-in-matlab#answer_281678: The function is 10% faster with bsxfun compared to auto-expansion in R2016b. The auto-expansion is nice, but I have the impression, that the implementation is much less efficient than bsxfun.
Image Analyst
2017-9-15
A(m,n)= (m-1)*100+n;
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