Finding specfic string within another string

1 次查看（过去 30 天）
Simon
Simon 2017-9-18
回答： Lucas Silva 2018-11-26
I am having trouble finding a specific part of a file path. The path is something along: \\blabla\blabla\blabla\blabla\blabla\blabla\04 - Black\05 - TEST
I need to find "04 - Black" in the path name. The name is changing and so is its position in the path - Therefor I need to find the first instance of 'XX - '. Afterwards I need to find the "05 - TEST" folder, which is also changing name and position.
Can anyone help?

请先登录，再回答此问题。

回答（5 个）

KSSV
KSSV 2017-9-18
编辑：KSSV 2017-9-18
str1 = '\\blabla\blabla\blabla\blabla\blabla\blabla\04 - Black\05 - TEST';
str2 = '04 - Black' ;
idx = strfind(str1,str2)
str1(idx:(idx+length(str2)-1))
José-Luis
José-Luis 2017-9-18
yourStr = '\blabla\blabla\blabla\blabla\blabla\blabla\04 - Black\05 - TEST'
re = '\\[0-9]{2}\s-\s[a-zA-Z]+';
result = regexp(yourStr,re,'match');
  1 个评论
Guillaume
Guillaume 2017-9-18
Other possible regex, which is more permissive:
re = '\\[0-9]{2}\s-\s[^\\]+';
Allows anything that is not \ after the two digits, whitespaces, and dash.

请先登录，再进行评论。

Guillaume
Guillaume 2017-9-18
if the aim is to obtain the name of the folder after the 'XX - ', then:
folder = regexp(path, '(?<=\\[0-9]{2}\s-\s[^\\]+\\)[^\\]+', 'match', 'once')
Cedric
Cedric 2017-9-18
Why not simply
>> str = '\\blabla\blabla\blabla\blabla\blabla\blabla\04 - Black\05 - TEST' ;
>> folders = regexp( str, '\d\d - [^\\]+', 'match' )
folders =
1×2 cell array
'04 - Black' '05 - TEST'
  5 个评论
显示 3更早的评论
Image Analyst
Image Analyst 2017-10-8
Those functions may return backslashes, but you can use forward slashes in your strings that you make up and send into functions like that with no problems. Like Stephen says, Windows accepts either forward or backward slashes equally well.
Cedric
Cedric 2017-10-8
编辑：Cedric 2017-10-8
Yes but we need to match a sub-string in this context and for this he needs to use the correct separator in the pattern, for REGEXP to work. He could use both for ending the match by defining the pattern as '\d\d - [^\\/]+'.
But again, if there is no problem in the "other direction" (because MATLAB can deal with either filesep), here both possibilities have to be managed, either by building the pattern using filesep or by making the pattern flexible enough.

请先登录，再进行评论。

Lucas Silva
Lucas Silva 2018-11-26
Eu tenho que fazer um processo semelhante, mas o método de separar as seqüências de caracteres é o ';' Eu tentei identificar o; como se fosse parte do comando, mas o matlab não aceita como.
Existe alguma maneira de obter essa informação?

类别

在 Help Center 和 File Exchange 中查找有关 Characters and Strings 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by