What is problem?

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Haseeb Hassan 2017-9-19

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评论： Haseeb Hassan 2017-9-25

采纳的回答： Jan

I want to apply this code on another image, but i am getting this problem, and the image can not be shown.

Please any help

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KSSV 2017-9-19

Haseeb Hassan it is a big matrix of 3D. Why you want to view it? There is no necessity to see it.

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采纳的回答

Jan 2017-9-19

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编辑：Jan 2017-9-19

The Variable Editor is not thought to display the contents of huge and/or 3D arrays. It is simply not useful to display them as a table. Therefore the behavior is expected and useful - and not a "problem". Use another tool to display the array, e.g. the image command.

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Image Analyst 2017-9-23

在 MATLAB Online 中打开

I don't advise you to call your image Image since there is a built in function called image. So let's call your grayscale image grayImage. Then to create an rgb image in the range 0-1, you can simply do

rgb = cat(3, grayImage, grayImage, grayImage) / 255;

Instead of all those lines of code you were using.

Haseeb Hassan 2017-9-25

Thanks Sir @ImageAnalyst and @WalterRoberson.I got you people points.Now i am doing detection in this three channel image so how useful it will be,i am compare to gray image, what advantages will this three channels image now to further crack down this three channel image as compared to single channel image(gray image).Thanks for you people responses.Cheers

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