Hi, I have a 150*54 matrix and a table of 18 labels ,and i want to named each 3 column of my matrix(which is 54) by 1 label

2 次查看(过去 30 天)
Hi, I have a 150*54 matrix and a table of 18 labels ,and i want to named each 3 column of my matrix(which is 54) by 1 label ,how it possible ? Thanks in advance

采纳的回答

Walter Roberson
Walter Roberson 2017-9-20
Is column 3 a numeric index into the label list?
%prepare some data for test purposes
your_labels = {'a', 'and', 'because', 'excessively', 'hamster', 'manager', 'me', 'not', 'obeyed', 'smart', 'some', 'system', 'tall', 'terrified', 'the', 'to', 'told', 'young'}; %18 labels
your_matrix = rand(150, 54);
your_matrix(:,3) = randi(length(your_labels), 150, 1);
%now do the work
V = @(M) M(:);
result = [num2cell(your_matrix(:,1:2),2), V(your_labels(your_matrix(:,3))), num2cell(your_matrix(:,4:end),2)];
Though you might prefer,
result = [V(your_labels(your_matrix(:,3))), num2cell(your_matrix(:,[1:2,4:end]),2)];

更多回答(1 个)

KL
KL 2017-9-19
your_matrix = rand(150,54);
C = mat2cell(your_matrix,150,repmat(3,1,18));
% your_labels = 1x18 cellarray
T = cell2table(C,'VariableNames',your_labels);
  4 个评论
KL
KL 2017-9-20
Or just use an array of structs..
your_matrix = rand(150,54);
C = mat2cell(your_matrix,150,repmat(3,1,18));
your_labels = {'a', 'and', 'because', 'excessively', 'hamster', 'manager', 'me', 'not', 'obeyed', 'smart', 'some', 'system', 'tall', 'terrified', 'the', 'to', 'told', 'young'}; %18 labels
for k=1:numel(your_labels)
labelled_data(k).label = your_labels(k);
labelled_data(k).values = C{k};
end

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Large Files and Big Data 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by