problem having reading the IP address in sorting

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Karan
Karan 2012-4-17
i asked a question here and sir andrei bobrov came out with a good solution here http://www.mathworks.in/matlabcentral/answers/34805-sorting-and-counting
a = [ 1 2 5 7] ; b = [ 9 9 3 4] ;
[aa bb] = ndgrid(a,b);
k = [aa(:) bb(:)];
[n1, n2, n2] = unique(k,'rows');
n3 = histc(n2,1:max(n2));
out = [n1, n3]
but what i ask is if i have to input a cell with values as
['172.20.1.1' '172.20.0.31' '172.20.114.29']
and perform the same program i am getting error as
??? Undefined function or method 'full' for input arguments of type 'cell'.
Error in ==> ndgrid at 38
varargin{i} = full(varargin{i}); % Make sure everything is full
Error in ==> bob at 3
[aa bb] = ndgrid(a,b);
any solutions please ??

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2012-4-18
a = { '172.20.113.214'
'85.17.72.66'
'172.20.113.214'
'38.124.168.125'
'46.45.178.252'
'172.20.113.214'
'46.45.178.252'
'172.20.113.214'
'172.20.113.1'
'46.45.178.252'
'172.20.113.214'
'46.45.178.252'
'172.20.113.214'
'46.45.178.252'
'172.20.113.214'
'38.124.168.125'
'172.20.113.214'
'38.113.165.77'
'172.20.113.214'
'38.124.168.125'
'172.20.113.214'
'95.211.85.42'
'172.20.113.214'
'38.113.165.77'
'172.20.113.214'}
[b n n] = unique(a);
out0 = accumarray(n,ones(numel(a),1));
out = [b, num2cell(out0)]
EDIT on comment
[A na na] = unique(a);
[B nb nb] = unique(b);
[av bv] = ndgrid(na,nb);
[v,nab,nab] = unique([av(:) bv(:)],'rows');
k = accumarray(nab,ones(numel(nab),1));
out = [A(v(:,1)) B(v(:,2)) num2cell(k)];
  2 个评论
Karan
Karan 2012-4-18
i though i have been misinterpreted by you sir , b is already given similar to a , check the pastie for the sample values of both a and b
sorry for less of info in last question
http://pastie.org/3809507
Karan
Karan 2012-4-18
hey andrei, i screwed myself , i got my problem statement wrong and i will have to get back ..thanx for the solution

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更多回答（2 个）

Walter Roberson
Walter Roberson 2012-4-17
You do not show us what your "a" and "b" are for this purpose, but you cannot ndgrid a cell array. You might want to look at bsxfun(). On the other hand, it looks to me as if you should probably be using accumarray()
  1 个评论
Karan
Karan 2012-4-18
take a = ['192.168.1.1' '192.168.1.2' '192.168.1.3' ... ] and b also similar
look for http://pastie.org/3809096

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Jan
Jan 2012-4-18
I guess, that you do not have:
a = ['172.20.1.1' '172.20.0.31' '172.20.114.29']
but
a = {'172.20.1.1' '172.20.0.31' '172.20.114.29'}
Andrei's solution works for number only. Therefore you could convert the string into numbers:
ac = {'172.20.1.1' '172.20.0.31' '172.20.114.29'}
a = zeros(size(ac));
for i = 1:numel(ac)
d = sscanf(ac{i}, '%d.%d.%d.%d');
a(i) = [16777216, 65536, 256, 1] * d;
end
The same for b.
  2 个评论
Karan
Karan 2012-4-18
yeah , thanx for the solution , but i want to continue with the IP address itself :)
Jan
Jan 2012-4-18
The contents of [a] *are* the IP address, but in binary form. The conversion back to strings after processing works equivalenty.

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