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replace all the array with NaN if any of the value is NaN

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khan
khan 2017-9-27
评论： Stephen23 2017-9-27
i am working with some data and the condition i want to set is that, if in the data there is NaN value in any column i want to replace that whole column with NaN values. following is a screen shot of my data structure. where i am working on the third dimension (144) of the data. Thanks in advance for help

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KSSV
KSSV 2017-9-27
编辑：KSSV 2017-9-27
% Generate random matrix
N = 10 ;
A = rand(10) ;
% introduce nans
idx = randsample(1:N*N,20) ;
A(idx) = NaN ;
%%Repalce columns with NaN's if any NaN'present
B = A ;
for i = 1:N
if any(isnan(A(:,i)))
B(:,i) = NaN ;
end
end

更多回答（1 个）

Jan
Jan 2017-9-27
Without a loop and bsxfun:
A = randi(9, 4, 3, 2);
A(6) = NaN;
A(:, any(isnan(A), 1)) = NaN;

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