Hi i'm new to Matlab. I have a matrix of 3985* 720, i want to produce a new matrix from this by averaging every 2 rows (1992*720), i would appreciate if someone can help me on this .

Question

Duminda Vidana Gamage 2017-9-27

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/358586-hi-i-m-new-to-matlab-i-have-a-matrix-of-3985-720-i-want-to-produce-a-new-matrix-from-this-by-aver

评论： Jan 2017-9-27

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Jan 2017-9-27

2
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/358586-hi-i-m-new-to-matlab-i-have-a-matrix-of-3985-720-i-want-to-produce-a-new-matrix-from-this-by-aver#answer_283360

编辑：Jan 2017-9-27

在 MATLAB Online 中打开

data    = rand(3985, 720);
nOut    = floor(size(data, 1) / 2);
dataCut = data(1:2*nOut, :);
dataAvg = sum(reshape(dataCut, 2, nOut, []), 1) * 0.5;
dataAvg = reshape(dataAvg, nOut, []);  % Or: squeeze(dataAvg)

Explanation:

Consider that M need not be a multiple of 2
Reshape the [M x N] array to a [2 x M/2 x N] array
Sum over the first dimension and divide by 2
Remove the first dimension to get a 2D matrix again

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Jan 2017-9-27

在 MATLAB Online 中打开

Please open a new thread for a new question. Then include the current code and explain, what "does not work" means. The solution will be something like this:

Base       = 'C:\YourPath';
FolderList = dir(Base);
FolderList = FolderList([FolderList.isdir]);
for iFolder = 1:numel(FolderList)
   aFolder = fullfile(Base, FolderList(iFolder).name);
   ... Do what you want
end