Nested For Loop Puzzle

2012 4 18
3 个回答
2 次查看（30 天）

0 个投票

please can anyone help me solve this Mats lab assignment
Q.Nested for loop that can solve this puzzle
T H I S W A T S O A H G G G D T
thank you

5 个评论
显示 3更早的评论 隐藏 3更早的评论

Jan
Jan 2012-4-18
Dear Samuel, you forgot to mention what kind of result you are looking for. Do you want the characters to be sorted alphabetically?
And as for all other homework questions: Please post what you have tried so far and explain, which problems you have. Of course a forum is not a place where homework questions are solved such that you can submit a solution by cut&paste.
Samuel Awuah Botwe
Samuel Awuah Botwe 2012-4-18
the questions was placed this way
please sir can you please help me solve this Mathslab assignment
Q.Nested for loop that can find this puzzle
T H I S
W A T S
O A H G
G G D T
Jan we are New students and we really dont know much about Matlab .was given us by a lecturer on first lecture day.please help me out.thanks
Thomas
Thomas 2012-4-18
since this is an assignment we can only help you on the basis of what you have don so far.. and where you are getting stuck..
Jan
Jan 2012-4-18
The program is called "Matlab".
The question is not clear. There is no obvious way to "find this puzzle". And this does not concern the Matlab implementation, but it is simply not defined, what you should do with these 16 characters.
Samuel Awuah Botwe
Samuel Awuah Botwe 2012-4-18
THIS WHAT I FIGURED OUT BUT GET AN ERROR CAN U PLEASE CHECK THE CODES FOR ME
m=[T,H,I,S;W,A,T,S;O,A,H,G;G,G,D,T]
l=size(m)
for i=1:l(1)
for j=1:l(2)
m(i,j) = m(i,j) * 2;
end
end
JUST AS THIS WORKS OUT AND DISPLAYS,HOW DO I MAKE IT DISPLAY IN ALPHABETS.....PLEASE TRY THIS CODE FOR ME....
m=[1,2,3,4;5,6,7,8;9,10,11,12]
l=size(m)
for i=1:l(1)
for j=1:l(2)
m(i,j) = m(i,j) * 2;
end
end

请先登录，再进行评论。

请先登录，再回答此问题。

回答（3 个）

Sean de Wolski
Sean de Wolski 2012-4-18

1 个投票

Golf:
reshape(['THISWATSOAHGGGDT'],4,4)'
Okay with for-loops:
for ii = 1
for jj = 1
m = reshape(['THISWATSOAHGGGDT'],4,4)';
end
end

3 个评论
显示 1更早的评论 隐藏 1更早的评论

Thomas
Thomas 2012-4-18
Sean, they have to use nested for loops.. I guess thats an assignment requirement..
Sean de Wolski
Sean de Wolski 2012-4-18
See the edit. Now with nested FOR-loops!
Thomas
Thomas 2012-4-18
:) Now why did I not think about it.. I do not know how I would grade a student if they returned an answer like yours above..
Technically they used nested for loops.. :)

请先登录，再进行评论。

Thomas
Thomas 2012-4-18

0 个投票

You are on the right track, to get alphabets..
try
%this is your input
a=['T' 'H' 'I' 'S' 'W' 'A' 'T' 'S' 'O' 'A' 'H' 'G' 'G' 'G' 'D' 'T']
% You need the two for loops.. that you have created above.. however you have to make sure you get the length of the loops rights..
P.S. Make sure you are not inputting your matrix in the output form itself.. the input should be an array as mentioned above.. and in your question.. You have to get it into 4x4 matrix using loops..

8 个评论
显示 6更早的评论 隐藏 6更早的评论

Samuel Awuah Botwe
Samuel Awuah Botwe 2012-4-18
i tried this
a=['T' 'H' 'I' 'S' 'W' 'A' 'T' 'S' 'O' 'A' 'H' 'G' 'G' 'G' 'D' 'T']
l=size(m)
for i=[T,H,I,S;W,A,T,S;O,A,H,G;G,G,D,T]
for j=1:l(2)
m(i,j) = m(i,j) * 2;
end
end
but still gets errors,what am i getting wrong in the for loop
Thomas
Thomas 2012-4-18
You need a new matrix of size 4x4
so your for loops must go from 1:4..
You are on the right track.. however l cannot be size(m) since your input is a, l can be size(a)
Samuel Awuah Botwe
Samuel Awuah Botwe 2012-4-18
I TRIED THIS AND THIS WAS THE ANSWER:
a=['T' 'H' 'I' 'S' 'W' 'A' 'T' 'S' 'O' 'A' 'H' 'G' 'G' 'G' 'D' 'T']
l=size(a)
for i=1:4(1)
for j=a:A(2)
m(i,j) = m(i,j) * 2;
end
end
a =
THISWATSOAHGGGDT
l =
1 16
ans =
1
HAVE ALSO TRIED THIS AND IT GIVES ME AN ERROR (Undefined function or variable 'T'.);
a=[T,H,I,S;W,A,T,S;O,A,H,G;G,G,D,T]
l=size(a)
for i=1:4(4)
end
end
I THINK YOUR ANSWER IS GETTING ME CLOSE BUT AM NOT GETTING SOMETHING RIGHT
Thomas
Thomas 2012-4-18
let me break it down for you
a=['T' 'H' 'I' 'S' 'W' 'A' 'T' 'S' 'O' 'A' 'H' 'G' 'G' 'G' 'D' 'T']
for i=1:4
m(i)=a(i);
end
m
This will give you the first line.. how do you go to the next line?
nested for loop.. get the next 4 alphabets.. how? increment the value in the loop get all the alphabets....
try a google search for 'matrix reshape nested for loop', you might get some basics..
This is a homework so I cannot give help with the code directly without causing you to cheat!!
Samuel Awuah Botwe
Samuel Awuah Botwe 2012-4-18
tHANKS ALOT,SO MUCH HELPFUL.GOD BLESS
Samuel Awuah Botwe
Samuel Awuah Botwe 2012-4-18
ITS ACTUALLY HELPFULL BUT MY ANSWERS NEEDS TO BE DISPLAYED AS ;
T H I S
W A T S
O A H G
G G D T
Thomas
Thomas 2012-4-18
yeah you need to input the next for loop as well.. how far is your code right now..
Thomas
Thomas 2012-4-18
let me give you some pseudo code... to define the logic
input array; (1x16)
start first row (i) (for loop)
place first element of input array into first row (i) of new matrix (for loop j)
increment your row (i) place the next four alphabets
and do so till you get all your elements in the new matrix..

请先登录，再进行评论。

Samuel Awuah Botwe
Samuel Awuah Botwe 2012-4-18

0 个投票

AM STILL FIGURING OUT WHAT AM MISSING IN THE CODE WITH THE GREAT HELP GIVEN ME.SEAN's SOLUTION WORKED RIGHT BUT I GUESS IT HASNT GOT THE FOR LOOP..........AM SOO THANKFULL FOR ALL YOUR EFFORT......I CANT WAIT TO GET IT RIGHT BEFORE I LEAVE FOR LECTURES IN 20 MIN TIME SINCE I NEED TO PRESENT IT TODAY

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

Jan
Jan 2012-4-19
Please note, that writing uppercase means shouting.

请先登录，再进行评论。

类别

在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by