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arrenging rows and columns ?

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pruth
pruth 2017-11-23
评论： Jan 2017-11-23
suppose i have latitude
-90
-60
-30
00
30
60
90
and longitude
-160 -120 -80 -40 00 40 80 120 160
i want output as
-90 -160
-60 -160
-30 -160
00 -160
30 -160
60 -160
90 -160
-90 -120
-60 -120
-30 -120
00 -120
30 -120
60 -120
90 -120
.
.
.
like that for all points. Any idea how could i do that ?

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采纳的回答

Jan
Jan 2017-11-23
编辑：Jan 2017-11-23
lat = [-90 -60 -30 00 30 60 90]';
long = [ -160 -120 -80 -40 00 40 80 120 160 ];
nLat = length(lat);
nLong = length(long);
both = [repmat(lat, nLong, 1), repelem(long(:), nLat, 1)];
Alternatively for old Matlab versions, which do not have repelem:
tmp = repmat(long, nLat, 1);
both = [repmat(lat, nLong, 1), tmp(:)];

更多回答（2 个）

Andrei Bobrov
Andrei Bobrov 2017-11-23
lat = [-90 -60 -30 00 30 60 90]';
long = [ -160 -120 -80 -40 00 40 80 120 160 ];
[x,y] = ndgrid(lat,long);
out = [x(:),y(:)];
Birdman
Birdman 2017-11-23
编辑：Birdman 2017-11-23
a=[-90 -60 -30 00 30 60 90];
b=[-160 -120 -80 -40 00 40 80 120 160];
a=a(:);b=b(:);
aa=repmat(a,length(b),1);
bb=repmat(b,length(a),1);
c=[aa bb]
  3 个评论
显示 1更早的评论
Jan
Jan 2017-11-23
@cvklpstunc: It works, but does not give the correct result: The 2nd column contains [-160; -120; -80; ...; 120; 160; -160; -120; ...] instead of the wanted [-160; -160; -160; ...]. It works, if you omit "b=b(:)" and reshape it after the repmat:
a = a(:);
aa = repmat(a,length(b),1);
bb = repmat(b,length(a),1);
c = [aa, bb(:)]

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