Problems solving cupled 2nd Order ODE with od45
1 次查看(过去 30 天)
显示 更早的评论
Hello.
I am given the task of simulating the two-dimensional motion of a magnetic pendulum in the x-y-plane. The problem comes down in solving this system of cupled 2nd order ordinary differential equation:
x'' + R*x' + sum_{i=1}^3 (m_i-x)/(sqrt((m1_i-x)^2 + (m2_i-y)^2 + d^2))^3 + G*x == 0
y'' + R*y' + sum_{i=1}^3 (m_i-y)/(sqrt((m1_i-x)^2 + (m2_i-y)^2 + d^2))^3 + G*y == 0
Those eqations discribe the motion in the plane. I know i can use the method "ode45" to solve such a problem, given some initial values.
I have tried it a few times, but didn't came to a solution.
I hope someone can help me. (x',y') = 0 no initial velocity and position (x,y) could be anywhere.
GREETINGS
4 个评论
回答(2 个)
Torsten
2017-11-29
M=@(t,y)[y(2);-R*y(2)+((mag1(1)-y(1))/(sqrt((mag1(1)-y(1))^2+(mag1(2)-y(3))^2+(mag1(3))^2)^3)+(mag2(1)-y(1))/(sqrt((mag2(1)-y(1))^2+(mag2(2)-y(3))^2+(mag2(3))^2)^3)+(mag3(1)-y(1))/(sqrt((mag3(1)-y(1))^2+(mag3(2)-y(3))^2+(mag3(3))^2)^3) )-C*y(1);y(4);-R*y(4)+((mag1(2)-y(3))/(sqrt((mag1(1)-y(1))^2+(mag1(2)-y(3))^2+(mag1(3))^2)^3) +(mag2(2)-y(3))/(sqrt((mag2(1)-y(1))^2+(mag2(2)-y(3))^2+(mag2(3))^2)^3) +(mag3(2)-y(3))/(sqrt((mag3(1)-y(1))^2+(mag3(2)-y(3))^2+(mag3(3))^2)^3) ) -C*y(3)];
Interval=[0 20];
Conditions = [x; dx/dt; y ; dy/dt] at t=0 ??
Solution = ode45(M,Interval,Conditions);
Best wishes
Torsten.
6 个评论
Steven Lord
2017-11-29
Consider specifying the 'OutputFcn' option in your ode45 call as part of the options structure created by the odeset function. There are a couple of output functions included with MATLAB (the description of the OutputFcn option on that documentation page lists them) and I suspect one of odeplot, odephas2, or odephas3 will be of use to you.
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Numerical Integration and Differential Equations 的更多信息
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!