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I am havng trouble with plotting this curve.

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sade chandler
sade chandler 2017-11-29
评论： VIGNESH BALAJI 2023-9-6
Cables are used to suspend bridge decks and other structures. If a heavy uniform cable hangs suspended from its two endpoints, it takes the shape of a catenary curve whose equation is where a is the height of the lowest point on the chain above some horizontal reference line, x is the horizontal coordinate measured to the right from the lowest point, and y is the vertical coordinate measured up from the reference line. Let a % 10 m. Plot the catenary curve for !20 # x # 30 m. How high is each endpoint?
So far I have
a=10 , y=a*cosh(x/a), x=-20:0.01:30; and plot(x,y),xlabel('x'),ylabel('y')

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回答（1 个）

Matt J
Matt J 2017-11-29
Since y depends on x, you must define x first:
a=10 ,
x=-20:0.01:30;
y=a*cosh(x/a),
plot(x,y),xlabel('x'),ylabel('y')
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DGM
DGM 2023-9-6
Ran in:
The curve is symmetric about x=0; since the vector x is not symmetric about 0, the endpoints are not the same height.
a = 10; % the height of the curve at x=0
x = -30:0.01:30; % x is now symmetric
y = a*cosh(x/a);
plot(x,y),xlabel('x'),ylabel('y')
VIGNESH BALAJI
VIGNESH BALAJI 2023-9-6
@DGM thank you for the nice explanation.
What should I do, if I want to draw a catenary at different heights entirely on positive x axis (with fixed y at both ends)?
I have been trying to do it.

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