Filename value extraction: code simplification

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Andreas B
Andreas B 2017-12-1
评论： Andreas B 2017-12-4
Being new to Matlab, it took me half a day to get my code to work at all, but now I'm wondering if it's possible to get it to work faster, in a better style and with less "detour" due to format-changing and such. It's a follow-up to a question I asked on Stack Overflow, but I find it to be more fitting to a forum like this here than S-O. Please tell me if you think it's better to stick to one platform ;)
What I want to do: I got files named abc123.xml, abc124.xml, abc133.xml etc. Now I just need the numerical value as a :,1 numerical array to be able to interactively select and process the data. This is what I got so far:
xml_filelist = dir('subfolder/*.xml'); % giving a :,1 struct with 5 fields where the first is the filename
xml_filelist = struct2table(xml_filelist); % converting it to a :,5 table where the first is the filename
xml_filelist = table2cell(xml_filelist(:,1)); % converting the first column to a cell array to be able to regexp it
xml_num = regexp(xml_filelist, '(\d+)', 'once', 'tokens'); % extracting the numerical value
xml_num = cellfun(@(x)str2double(x), xml_num); % converting it from string cell array to double values
This leaves me with an array like [123; 124; 133], which is what I need. Now is there any way to simplify the code above?

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Walter Roberson
Walter Roberson 2017-12-1
xml_filelist = dir('subfolder/*.xml');
xml_filenames = {xlm.filelist.name};
xml_num = str2double( regexp(xml_filenames, '\d+', 'match', 'once') );
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Andreas B
Andreas B 2017-12-2
I feel very stupid for that one, sorry. Will be the first thing I try on monday, as I it's a company license.

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