( need help ) nested for loops to print the following pattern

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reem alromaihi
reem alromaihi 2017-12-5
回答： emad xa 2020-4-6
Write a nested for loops to print the following pattern
A
BA
CBA
DCBA
EDCBA
I write my own code but the output is different any one can show me where is the mistake the code is :
for letter = 'A':'E'
for n= 'A':letter
fprintf(letter)
%fprintf(n)
end
fprintf('\n')
end
and the output is :
A
BB
CCC
DDDD
EEEEE
need help
  1 个评论
Guillaume
Guillaume 2017-12-5
A one-liner to generate that matrix:
char(toeplitz(65:69, [65, 32, 32, 32, 32]))
Obviously, not likely to be an accepted answer to this homework problem.

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回答（3 个）

Star Strider
Star Strider 2017-12-5
You have to count down from the present index of ‘letter’ in the loop to 1.
(It is difficult to illustrate it without providing the complete solution.)
Example —
letter = 'A':'E';
loop with index k1
k1 = 1
print letter(k1)
k1 = 2
print letter(k1), letter(k1-1) ...
...
end loop
Use fprintf('%s'\n', ...)|* to print the concatenated letter array.
KL
KL 2017-12-5
编辑：KL 2017-12-5
You have it almost right but I'd suggest to use for-loops for indexing through rows(lines) and columns(individual character). Also initially you can create your character vector.
For example,
charVec = 'A':'E';
now you have all the possible characters here in this variable. Next is to use your for loops,
for letter = 1:length(charVec)
...
so first loop is for number of lines, as many lines as your number of characters.
for n= letter:-1:1
now as you see, second loop starts from the value of first loop's iterator ( letter) and goes backwards until 1. Why? Because you want to print in reverse order, right?
Now, print it inside the loop and finish the rest.
  3 个评论
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KL
KL 2017-12-6
for n= -1:1:letter
this is not what I suggested. Even if you corrected it, you should not print n but the n-th element in r
Stephen23
Stephen23 2017-12-6
@reem alromaihi: note that KL wrote "I'd suggest to use for-loops for indexing...".

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emad xa
emad xa 2020-4-6
how to do
A B C D E
A B C D
A B C
A B
A

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