( need help ) nested for loops to print the following pattern

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reem alromaihi 2017-12-5

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回答： emad xa 2020-4-6

Write a nested for loops to print the following pattern

A
BA
CBA
DCBA
EDCBA

I write my own code but the output is different any one can show me where is the mistake the code is :

for letter = 'A':'E'
     for n= 'A':letter
        fprintf(letter)
              %fprintf(n)
         end
        fprintf('\n')
     end

and the output is :

A
BB
CCC
DDDD
EEEEE

need help

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Guillaume 2017-12-5

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A one-liner to generate that matrix:

char(toeplitz(65:69, [65, 32, 32, 32, 32]))

Obviously, not likely to be an accepted answer to this homework problem.

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Answer 1

Star Strider 2017-12-5

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You have to count down from the present index of ‘letter’ in the loop to 1.

(It is difficult to illustrate it without providing the complete solution.)

Example —

letter = 'A':'E';
loop with index k1
   k1 = 1
   print letter(k1)
   k1 = 2
   print letter(k1), letter(k1-1) ...
   ...
end loop

Use fprintf('%s'\n', ...)|* to print the concatenated letter array.

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Answer 2

KL 2017-12-5

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编辑：KL 2017-12-5

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You have it almost right but I'd suggest to use for-loops for indexing through rows(lines) and columns(individual character). Also initially you can create your character vector.

For example,

charVec = 'A':'E';

now you have all the possible characters here in this variable. Next is to use your for loops,

for letter = 1:length(charVec)
...

so first loop is for number of lines, as many lines as your number of characters.

for n= letter:-1:1

now as you see, second loop starts from the value of first loop's iterator ( letter) and goes backwards until 1. Why? Because you want to print in reverse order, right?

Now, print it inside the loop and finish the rest.