Working with dde23 for a simple problem
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I'm trying to solve this: xdot = -Lx(t-1) where x is a 3x1 vector and L a constant 3x3 matrix. The initial conditions for x are [0 0 0]'for t<0. For some reasons, I'm having trouble with framing the DDE.I have seen the comprehensive manual already. Yours inputs are appreciated. Thanks.
4 个评论
Torsten
2017-12-12
Solution is x=[0 0 0] for all t.
Best wishes
Torsten.
Deepayan Bhadra
2017-12-12
Torsten
2017-12-12
Why ?
Deepayan Bhadra
2017-12-12
采纳的回答
Jan
2017-12-12
0 个投票
If x is [0;0;0] for t < 0 and xdot = -L * x(t-1), you get xdot=[0;0;0] for the time 0<=t<=1. If you integrate this, x will remain [0;0;0] and this argument can be expanded to the following intervals also.
2 个评论
Deepayan Bhadra
2017-12-12
Jan
2017-12-12
Yes. But you are asking for [0;0;0] explicitly.
Did you read https://www.mathworks.com/matlabcentral/fileexchange/3899-tutorial-on-solving-ddes-with-dde23 already? Maybe it would be helpful if you explain, which problem you have. "For some reasons, I'm having trouble with framing the DDE" does not reveal, which troubles you are faced with.
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