Find nearest value to specific number

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Hello, I have an array with 20 values of steps per minute. I already know that the perfect outcome of one of these values is 33spm. But unfortunately 33spm is not in the array 34.8 is which is the closest to 33. What is the code to find the value closest to 33?
The ideal answer would be:
ClosestValue = 34.8
Could someone help me please?

采纳的回答

Birdman
Birdman 2018-1-5
编辑:Birdman 2018-1-5
Try the following approach:
a=[34.8 31 29 26.7 39.5];%dummy data
n=33;
[val,idx]=min(abs(a-n));
minVal=a(idx)
Edit after Jan's warning(multiple values)
a=[34.8 31.2 29 26.7 39.5];%dummy data
n=33;
[~,~,idx]=unique(round(abs(a-n)),'stable');
minVal=a(idx==1)
  17 个评论
Umesh Gautam
Umesh Gautam 2023-8-29
编辑:Umesh Gautam 2023-8-29
Thanks @Birdman, code is working great...even one can find the array of values.

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更多回答(2 个)

Walter Roberson
Walter Roberson 2018-1-5
Use interp1 with 'nearest'
Or since the vector is small abs() the difference between the probe and the fixed values and min() that and take the second output of min() and use that to index the fixed values. This is not as convenient as interp1 but should be faster

Atique Barudgar
Atique Barudgar 2019-11-8
I am not clear how Birdman SIr's answer came
when idx =1
then how a(idx)=34.8
I didnt got how and what is idx

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