Plotting a Step Function

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Adam Makin
Adam Makin 2018-1-8
编辑： Jan 2018-1-8
The following function f(t,T,x) returns the following. 1 if qT ≤ t < (q + x)T 0 if (q + x)T ≤ t < (q + 1)T
I know this is a step function and I think it involves using heaviside, however I have no idea really where to start in order to plot the function. q, x and T are to be defined by me. THis is the code I have so far:
function v=pwm(t,T,d)
d = 0.5;
T= 0.01;
k = 1;
t=linspace(0,0.2,100);
v(k*T<=t<k+d) = 1;
v((k + d)*T <= t < (k + 1)*T) = 0;
plot(t,v)
q I changed for k (q=k) and x = d.
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Adam Makin
Adam Makin 2018-1-8
Sorry you are right I should be much more specific, I wanted to plot the function.
Jan
Jan 2018-1-8
Sorry, I didn't want to let you be sorry. Questions for clarifications are usual in the forum, because it is the nature of question, that some details are not clear to the asking person. :-)

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回答（2 个）

Star Strider
Star Strider 2018-1-8
Try this:
f = @(t,T,x,q) (1.*((q.*T <= t ) & (t < (q+x).*T))) + (0.*(((q+x).*T <= t) & (t < (q+1).*T)));
q = 1;
x = 0.5;
T = 0.01;
t = linspace(0,0.2,100);
figure(1)
plot(t, f(t,T,x,q), '-r')
axis([xlim 0 1.1])
grid
Jan
Jan 2018-1-8
编辑：Jan 2018-1-8
What about this:
t = [q*T, (q + x) * T, (q + x) * T, (q + 1) * T]; % [EDITED, Typo fixed]
y = [1, 1, 0, 0];
plot(t, y)
This is a line through 4 points. Is this sufficient to plot the function, if you define q, T and x accordingly? Note that 0 < x < 1 seems to be required.
If you want something else, please explain the difference to this simple approach.
  2 个评论
Adam Makin
Adam Makin 2018-1-8
sorry trying to run this I receive the error:
Error using plot Vectors must be the same length.
Jan
Jan 2018-1-8
编辑：Jan 2018-1-8
@Adam: Sorry, a typo.
t = [q*T, (q + x) * T, (q + x) * T, (q + 1) * T];
^ comma instead of colon
Is the idea of my suggestion clear?

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