Caught in loop

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Dejan Cvijanovic
Dejan Cvijanovic 2012-5-7
My code is as follows:
alpha = 0.5;
beta = 0.1;
a_0 = 1;
dr = 0.1;
dt = input('Value of dt:');
h = 0.001;
c_inf = 0;
c_a = 1;
c_s = 2;
mesh_points = 3;
rho = dt/(dr)^2;
R= 30;
N_i = R/dr;
t_diss = 5.8;
N_t = t_diss/dt;
if rho >= 0.5;
disp('Invalid dt value');
return;
end
for i=1:N_i;
r(i)=(i-1)*dr;
if r(i)< a_0
c(i,1)= c_s;
else
c(i,1)= c_inf;
end
end
a(1) = a_0;
for j = 1:N_t -1;
b_1 = floor (a(j)/dr) + 2;
b_2 = b_1 + 1;
c_ah = (a(j)+h-b_1)*(a(j)+h-b_2)*(c_a)/((a(j)-b_1)*(a(j)-b_2))+h*(a(j)+h-b_2)*c(b_1,j)/((b_1-a(j))*(b_1-b_2)) + h*(a(j)+h-b_1)*c(b_2,j)/((b_2-a(j))*(b_2-b_1));
dc_dr = ((c_ah)-c_a)/h;
a(j+1) = a(j) +dt*beta*dc_dr;
for i=2:N_i - 1;
if r(i) > a(j+1);
d = rho - (rho/(i-1)) - (a(j)^2)*(alpha-1)*(a(j+1)-a(j))/(2*(i-1)^2*(dr)^3);
e = 1-2*rho;
f = rho + (rho/(i-1)) + (a(j)^2)*(alpha-1)*(a(j+1)-a(j))/(2*(i-1)^2*(dr)^3);
c(i, j+1) = d*c(i-1,j) + e*c(i,j) + f*c(i+1, j);
elseif r(i) == a(j+1);
c(i,j+1) = c_a;
else c(i,j+1) = c_s;
end
disp(c(i,j));
end
c(1, j+1) = c(2, j+1);
end
It basically calculates concentration near a dissolving sphere but when it gets to disp(c(i,j)) I get caught in loop of displaying numbers that change periodically. Any ideas?

采纳的回答

Jan
Jan 2012-5-7
And some cleanup:
...
% Vectorization of the "for i=1:N_i;" loop:
r = (0:N_i) * dr;
c = zeros(N_i, N_t - 1); % Pre-allocate!
c(:, 1) = c_inf;
c(r < a_0, 1) = c_s;
...
dr3 = dr ^ 3;
...
% Reduce repeated calculations inside the "for j = 1:N_t -1" loop:
ajp1 = a(j) +dt*beta*dc_dr;
a(j+1) = ajp1;
tmp1 = (a(j)^2) * (alpha-1) * (ajp1-a(j)) / (2 * dr3);
for i = 2:N_i - 1
if r(i) > ajp1
tmp2 = rho / (i-1) + tmp1 / ((i-1)^2);
d = rho - tmp2;
e = 1 - 2 * rho;
f = rho + tmp2;
c(i, j+1) = d*c(i-1,j) + e*c(i,j) + f*c(i+1, j);
elseif r(i) == ajp1
c(i, j+1) = c_a;
else
c(i, j+1) = c_s;
end
% disp(c(i,j));
end
  5 个评论
Dejan Cvijanovic
Dejan Cvijanovic 2012-5-7
Got an error: Attempted to access a(1); index out of bounds because numel(a)=0.
Error in CleanDiss (line 36)
ajp1 = a(j) +dt*beta*dc_dr;
Ideas?
Dejan Cvijanovic
Dejan Cvijanovic 2012-5-7
I fixed the error and get these numbers (which make sense):
0.4011
0.3037
0.3882
0.2886
0.3634
0.2649
0.3293
0.2350
0.2886
0.2014
0.2447
0.1667
0.2006
0.1333
0.1589
0.1028
0.1217
0.0766
0.0900
0.0550
0.0643
0.0381
0.0443
0.0254
0.0294
0.0164
0.0189
0.0101
They generally decrease, which is correct but some of them increase, which shouldn't be true?

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更多回答(1 个)

Richard Brown
Richard Brown 2012-5-7
Your code works fine. If you remove the disp statement (which is causing it to slow down heaps), you'll find that it runs completely in around 10 seconds or so.
  2 个评论
Richard Brown
Richard Brown 2012-5-7
Oh, and a hint: Select all the code, then Text->Smart Indent
Image Analyst
Image Analyst 2012-5-7
Cool. Nice trick that I didn't know about.

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