Structure Assginment
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I need a better approach to assign matrix to a structure. Currently I have
A = 5 by 1 struct with Loc & Err variables, A(1:5).Loc & A(1:5).Err,
I have Values matrix 5 by 6 where Loc info stored.
My code;
for i=1:5
A(i).Loc = Values(i,:)
end
Is there easy way of assignment. I have a very complex structure, this is very simplified version of it. Any ideas??
1 个评论
Daniel Shub
2012-5-8
This seems pretty easy to understand for me. What do you mean by easy?
采纳的回答
Walter Roberson
2012-5-8
Try this:
vcell = mat2cell(Values, ones(1, size(Values,1)), size(Values,2));
[A.Loc] = vcell{:};
4 个评论
Umit
2012-5-8
Walter Roberson
2012-5-8
I had assumed here that you had already created A as a structure array. Otherwise,
[A(1:size(Values,1)).Loc] = vcell{:};
Daniel Shub
2012-5-8
If there are lots of fields you might want to consider cell2struct
Umit
2012-5-8
更多回答（1 个）
Jan
2012-5-8
1 个投票
There is no easy way to assign a very complicated structure.
Using a loop is most likely the easiest and most efficient method, especially if you use implicite pre-allocation by running the loop from the end to the start.
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