Sub values into multiple rows and columns simutaneously
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I have a 10x10 matrix. I want to sub a few values into the matrix simultaneously, with the other values being zero. It would be time-consuming to sub the values one by one. Is there any way to do this?
For example, A=[zeros(10,10)] A(1,1)=-4 A(2,2)=-4 A(3,3)=-4
Is there a way to sub -4 into these locations at once?
1 个评论
Jan
2018-1-19
Does "to sub" mean "subtract" or "substitute"? According to your code "substitute" is meant.
采纳的回答
Jan
2018-1-19
Replacing 3 elements is not time consuming and the show code is very efficient. If run time is critical, you are working on another problem, obviously. Then it is better to explain the real problem, and not a very simplified version of it, which omits the actual time consuming details.
If you want to replace some thousands of elements, whose indices are store in two vectors:
x = [1,2,3]; % Can be much longer
y = [1,2,3];
index = sub2ind(size(A), x, y);
A(index) = -4;
更多回答（2 个）
Walter Roberson
2018-1-19
0 个投票
Use sub2ind convert the row column pairs into linear indexing. Then index the left side with the linear indexes.
Jos (10584)
2018-1-19
The words " a few" and " others remaining zero" might indicate that you also could use SPARSE matrices. For instance:
A = sparse([1 2 3],[1 2 3],-4,10,10)
full(A)
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