Sysmsum gives wrong output

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Mohamed Musni
Mohamed Musni 2018-1-23
评论： Stephen23 2018-1-23
For this code im getting output as below. But its multiplied with 3 in every term. What am I doing wrong here? Because I don’t need that multiplication with 3
  1 个评论
Stephen23
Stephen23 2018-1-23
@Mohamed Musni: please do not post screenshots. It is actually easier for us when you post real text: this includes the code and any error messages. Real text can be searched (or searched for), edited, and run. Screenshots are basically useless in most cases.

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Birdman
Birdman 2018-1-23
Actually, your code displays the correct output because you try to implement the series sum with respect to a different variable k, which is not included in any of your other symbolic variables. Therefore your series turns into something that multiplying a constant value with m, which is 3 in this case.
((((q.*t)./2).*h)+P)./t
>> [q1 + 10, (3*q2)/2 + 10, 2*q3 + 10]
As you see, q symbolic variable is not dependent on k, therefore your symsum will be multiplied by m directly. 3 comes from that.
symsum(((((q.*t)./2).*h)+P)./t,k,1,m)
>> [3*q1 + 30, (9*q2)/2 + 30, 6*q3 + 30]
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Birdman
Birdman 2018-1-23
Yes, you can change the upper limit dependent on k as follows:
symsum(((((q.*t)./2).*h)+P)./t,k,1,m+k)
Mohamed Musni
Mohamed Musni 2018-1-23
Thank you. have a nice day :D

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