How to write matrix elements with its position?

2018 1 25
3 个回答
回答已采纳
更新时间：2018 1 25
13 次查看（30 天）

0 个投票

I have a matrix A=[1 2 3; 4 5 6; 7 8 9] I want to write each entry with its row and column position e.g 111 indicates the element 1 at position first row First column , also 328 element 8 at position 3rd row and second column. so with the help of above matrix
A I want the following
111
122
133
214
225
236
317
328
339
Thanking for the anticipation.

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

Guillaume
Guillaume 2018-1-25
While it's very easy to do what you want, what is its purpose? Bearing in mind that if you don't limit A to integers [0-9] and its size to a max of 9 rows and 9 columns, then the operation is irreversible.
What would the value 1234 mean?
  • 1st row, 2nd column, value 34?
  • 12th row, 3rd column, value 4?
  • 1st row, 23rd column, value 4?

请先登录，再进行评论。

请先登录，再回答此问题。

 采纳的回答

Birdman
Birdman 2018-1-25
编辑：Birdman 2018-1-25

0 个投票

[r,c]=find(A);
val=sortrows([r c A(:)],1)

2 个评论
显示 无 隐藏 无

Guillaume
Guillaume 2018-1-25
That will fail if any value in A is 0.
[r, c] = find(true(size(A));
val = sortrows([r c A(:)],1)
would be safer.
Or:
[c, r] = ndgrid(1:size(A, 2), 1:size(A, 1));
val = [r(:), c(:), a(:)];

请先登录，再进行评论。

更多回答（2 个）

Domanic
Domanic 2018-1-25

2 个投票

Or ind2sub:
A = [1 2 3; 4 5 6; 7 8 9].';
[a,b] = ind2sub(size(A),1:numel(A));
fprintf('%d%d%d\n',[b.' a.' A(:)].')
Jan
Jan 2018-1-25

1 个投票

What about loops?
A = [1 2 3; 4 5 6; 7 8 9];
[s1, s2] = size(A);
for i1 = 1:s1
for i2 = 1:s2
fprintf('%d%d%g\n', i1, i2, A(i1, i2));
end
end

类别

在 帮助中心 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by