Issue to begin TestBench generation.

Question

satish morigiri 2018-1-26

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/379058-issue-to-begin-testbench-generation

评论： satish morigiri 2018-1-31

采纳的回答： Kiran Kintali

在 MATLAB Online 中打开

Hi,

I'm trying to generate TestBench from 'Verify with HDL Test Bench' in Workflow Advisor.

the code is like this.

- test.m

clear all
clc
N = 128;
Fs = 40;
t = (0:N-1)'/Fs;
x = sin(2*pi*15*t) + 0.75*cos(2*pi*10*t);
y = x + .25*randn(size(x));
y_fixed = sfi(y,32,24);
Yf = zeros(1,3*N);
validOut = false(1,3*N);
for loop = 1:1:3*N
    if (mod(loop, N) == 0)
        i = N;
    else
        i = mod(loop, N);
    end
    [Yf(loop),validOut(loop)] = HDLFFT128(complex(y_fixed(i)),(loop <= N));
end
Yf = Yf(validOut == 1);
Yr =  bitrevorder(Yf);
plot(Fs/2*linspace(0,1,N/2), 2*abs(Yr(1:N/2)/N))
title('Single-Sided Amplitude Spectrum of Noisy Signal y(t)')
xlabel('Frequency (Hz)')
ylabel('Output of FFT (f)')

The below is HDLFFT128 function.

- HDLFFT128.m

    % function [yOut,validOut] = HDLFFT128(yIn,validIn)
    % %HDLFFT128 
    % % Processes one sample of FFT data using the dsp.HDLFFT System object(TM)
    % % yIn is a fixed-point scalar or column vector. 
    % % validIn is a logical scalar value.
    % % You can generate HDL code from this function.
    % 
    %   persistent fft128;
    %   if isempty(fft128)
    %     fft128 = dsp.HDLFFT('FFTLength',128);
    %   end    
    %   [yOut,validOut] = fft128(yIn,validIn);
    % end
function [yOut,validOut] = HDLFFT128(yIn,validIn)
%HDLFFT128 
% Processes one sample of FFT data using the dsp.HDLFFT System object(TM)
% yIn is a fixed-point scalar or column vector. 
% validIn is a logical scalar value.
% You can generate HDL code from this function.
    persistent fft128;
    if isempty(fft128)
      fft128 = dsp.HDLFFT('FFTLength',128);
    end    
    [yOut,validOut] = fft128(yIn,validIn);
  end