mink and maxk functions

8 次查看（过去 30 天）
UET Hussain
UET Hussain 2018-2-5
评论： UET Hussain 2018-9-5
I'm using MATLAB R2017a. While trying to use "mink" and "maxk" functions, the MATLAB responds "Undefined function or variable 'maxk'." These two functions were introduced in R2017b. Is it possible to use these functions with R2017a? if yes, then how?
  1 个评论
Stephen23
Stephen23 2018-2-5
"These two functions were introduced in R2017b. Is it possible to use these functions with R2017a?"
No.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Birdman
Birdman 2018-2-5
One approach would be writing your own function:
function y=mink(A,k)
A=sort(unique(A));
y=A(1:k);
end
Call this function from command line as follows
A=1:10;
mink(A,3)
and the first three smallest elements will be displayed.
  7 个评论
显示 5更早的评论
Jan
Jan 2018-2-5
mink does not reply unique elements. Therefore the correct replacement is:
function y = mink(A, k)
A = sort(A); % No UNIQUE here
y = A(1:k);
end
See: mink([1,1,2,3], 2) replies [1,1,2] .
Birdman
Birdman 2018-2-5
Mine approach was different, but anyway thanks Jan :)

请先登录，再进行评论。

更多回答（1 个）

Salam Ismaeel
Salam Ismaeel 2018-9-4
编辑：Salam Ismaeel 2018-9-4
% function [B BIndex RestVector]= maxk2(A, k)
% Find k largest elements in a Vector A
% B : Vector with all max elements (included repeated)
% BIndex : idx of max k element
% RestVector : rest of the elements without max k elements
function [B BIndex RestVector]= maxk2(A, k)
B = 0;
RestVector = A;
sumIndex = 1;
for i=1:k
MaxA = max(A);
I = A == MaxA;
sumI = sum(I); %To find number of Max elements (repeated)
B(sumIndex: sumIndex+sumI-1) = MaxA; % to same max elements in B
BIndex(sumIndex: sumIndex+sumI-1) = find(A == MaxA);
sumIndex = sumIndex + sumI;
A(I) = min(A); % exchange the max elements by a smallest value
end
RestVector(BIndex) = []; % remove largest values
------------------------------ Example ------------------
>> x
x =
4 17 65 73 65 45 55 30 74 19
>> [x1 x1idx x1new ] = maxk2(x,4)
x1 =
74 73 65 65 55
x1idx =
9 4 3 5 7
x1new =
4 17
  1 个评论
UET Hussain
UET Hussain 2018-9-5
Sir Sir Sir, slightly difficult approach. but its giving all required things. thanks for response.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Descriptive Statistics 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by