matrix multiplication with probability

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Santhosh Chandrasekar
评论： Santhosh Chandrasekar 2018-2-14
Hi, I want to assign a probability of multiplication for each value in a 3X3 matrix and multiply it by a random number. Can anyone please help me with this.
  2 个评论
Walter Roberson
Walter Roberson 2018-2-11
An example would help our understanding.
Santhosh Chandrasekar
Santhosh Chandrasekar 2018-2-11
编辑：Santhosh Chandrasekar 2018-2-12
Thank you Jan for your answer, I sincerely appreciate it. but my requirement is for example
A = [1 0.5 1; 0.6 0.3 0.4; 0.4 0.5 1];
K= 1:1:10
a = rand;
C= [a 0 0]; here i want to assign probabilities to the 3 positions of 'C' where 'a' can be assigned i.e C = [10% 20% 30%] so during every iteration, a random 'a' is generated and it is placed in one of the position of 'C' based on the assigned probability and 'C' will get multiplied with 'A'

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采纳的回答

Roger Stafford
Roger Stafford 2018-2-12
编辑：Roger Stafford 2018-2-12
If p is a matrix the same size as A with the probability values you describe, do this:
SA = size(A);
a = rand(SA);
A = A + (A.*a-A).*(rand(SA)<=p);
At each element of A it is multiplied by the random number in ’a’ with probability in the corresponding element in p. Otherwise the element is unchanged.
It is possible you meant 'a' to be a single random scalar value rather than a matrix of them. If so, change the code to:
a = rand;
A = A + ((a-1)*A).*(rand(size(A))<=p);
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显示 1更早的评论
Roger Stafford
Roger Stafford 2018-2-12
I will help with your comment request by showing you how to produce an index with the requested probabilities. You can then use that index in dealing appropriately with your matrix A.
P = [.1;.2;.3];
CP = cumsum(P);
r = rand;
ix = sum(CP<=r)+1;
Given the values in P, the index ‘ix’ will assume the values 1, 2, 3, or 4 with respective probabilities .1, .2, .3, and 1-(.1+.2+.3)=.4 . If you wish to do something in the case ix=4, you can write
if ix<=3
% Handle the ix = 1,2,3 cases
else
% Handle the ix = 4 case
end
Otherwise, just omit the ‘else’ part.

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更多回答（1 个）

Jan
Jan 2018-2-11
Maybe:
A = [1 0.5 1; 0.6 0.3 0.4; 0.4 0.5 1];
for k = 1:10
a = rand;
B = A * a;
...
end
  1 个评论
Santhosh Chandrasekar
Santhosh Chandrasekar 2018-2-12
编辑：Santhosh Chandrasekar 2018-2-12
Thank you Jan for your answer, I sincerely appreciate it. but my requirement is for example
A = [1 0.5 1; 0.6 0.3 0.4; 0.4 0.5 1];
K= 1:1:10
a = rand;
C= [a 0 0]; here i want to assign probabilities to the 3 positions of 'C' where 'a' can be assigned i.e C = [10% 20% 30%] so during every iteration, a random 'a' is generated and it is placed in one of the position of 'C' based on the assigned probability and 'C' will get multiplied with 'A'

请先登录，再进行评论。

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