Matrix Dimensions must agree using integral
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Hello all,
I am trying to integrate over a function.
% calculation of f(b)
b = exp((-q*Vj)/(2*kB*Temp))*cosh((Et-Ei)/((kB*Temp)+0.5*(log(tau_p0/tau_n0))));
% integrate over x while varying b
fcn_b = zeros(1,length(b));
fcn = @(x)1./((x.^2)+(2.*b.*x)+1);
fcn_b = integral(fcn,0,Inf);
end
But I receive an error after the fcn = @x line saying matrix dimensions must agree.
The size of b => 1 x 141. Any help would be appreciated.
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atsprink
2018-2-21
2 个投票
3 个评论
Benjamin
2019-11-6
I had the same error of
Error using /
Matrix dimensions must agree.
in an numerical integration in which the @(x) function is very complicated, and after I added 'ArrayValued',true it fixed my problem.
Thank you so.
Lucas Ivan
2023-2-23
Hello everyone! I was having the same error and I could solve it with this. However, any idea on why we need to add this argument?
However, any idea on why we need to add this argument?
If you don't add this argument, MATLAB calls your function to be integrated with a vector of values for the integration variable and expects your function to return a vector of the same size. This won't happen since your function itself is a vector of functions - depending on the vector b. If you set "ArrayValued" to "true", MATLAB "knows" that you want to integrate a vector-valued function and calls it only with single (scalar) values for the integration variable.
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