Storing a range as a variable
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Imagine the start and end values of a range being set from user input. They could be:
a=3;
b=10;
To extract this range from an array, I simply do:
x(a:b);
But I'd like to save this range as one variable in itself, so that I can insert the range easily many places and only have to change it in one place such as:
range=a:b;
x(range);
This gives an error. MatLab will not store the a:b in this manner since : is a string and I thus am mixing strings with numbers. I could convert the a and b into a string with num2str, but then that range cannot be inserted into the x variable.
Is there a way to do this or do I have to manually put together the range with x(a:b) every time?
采纳的回答
Angelo
2018-2-26
x=[0.1:0.1:2];
range=[3:10];
x(range)
1 个评论
Jan
2018-2-26
See: http://www.mathworks.com/matlabcentral/answers/35676-why-not-use-square-brackets . The additional square brackets waste time only. They are the concatenation operator, but "3:10" is a vector already and nothing is concatenated.
In addition it is worth to consider, that
x(a:b)
is faster than
v = a:b;
x(v)
because in the first case, the index vector a:b is not created explicitly.
更多回答(1 个)
Jan
2018-2-26
编辑:Jan
2018-2-26
What's wrong with
x(a:b)
You really need to store it in one variable?
Range.a = a;
Range.b = b;
x(Range.a : Range.b)
Or:
Range = {a,b};
x(Range{1}:Range{b})
You could write a function also:
GetInterval(x, Range)
function y = GetInterval(x, Range)
y = x(Range{1}:Range{b});
end
But this will be slower and worse to read than the direct and simple:
x(a:b)
Note that Matlab seems to avoid the explicit creation of the index vector a:b to save time in this case, but this is not documented.
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