Storing a range as a variable

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Steeven
Steeven 2018-2-26
编辑： Stephen23 2018-2-26
Imagine the start and end values of a range being set from user input. They could be:
a=3;
b=10;
To extract this range from an array, I simply do:
x(a:b);
But I'd like to save this range as one variable in itself, so that I can insert the range easily many places and only have to change it in one place such as:
range=a:b;
x(range);
This gives an error. MatLab will not store the a:b in this manner since : is a string and I thus am mixing strings with numbers. I could convert the a and b into a string with num2str, but then that range cannot be inserted into the x variable.
Is there a way to do this or do I have to manually put together the range with x(a:b) every time?
  2 个评论
Adam
Adam 2018-2-26
range = a:b;
is perfectly acceptable syntax. : is an operator here, not a string.
Stephen23
Stephen23 2018-2-26
编辑：Stephen23 2018-2-26
"This gives an error."
Not when I try it:
>> a = 3;
>> b = 10;
>> range = a:b
range =
3 4 5 6 7 8 9 10
See also the earlier question:
https://www.mathworks.com/matlabcentral/answers/384876-how-to-properly-input-a-range-in-a-vector

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采纳的回答

Angelo
Angelo 2018-2-26
x=[0.1:0.1:2];
range=[3:10];
x(range)
  1 个评论
Jan
Jan 2018-2-26
See: http://www.mathworks.com/matlabcentral/answers/35676-why-not-use-square-brackets . The additional square brackets waste time only. They are the concatenation operator, but "3:10" is a vector already and nothing is concatenated.
In addition it is worth to consider, that
x(a:b)
is faster than
v = a:b;
x(v)
because in the first case, the index vector a:b is not created explicitly.

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更多回答（1 个）

Jan
Jan 2018-2-26
编辑：Jan 2018-2-26
What's wrong with
x(a:b)
You really need to store it in one variable?
Range.a = a;
Range.b = b;
x(Range.a : Range.b)
Or:
Range = {a,b};
x(Range{1}:Range{b})
You could write a function also:
GetInterval(x, Range)
function y = GetInterval(x, Range)
y = x(Range{1}:Range{b});
end
But this will be slower and worse to read than the direct and simple:
x(a:b)
Note that Matlab seems to avoid the explicit creation of the index vector a:b to save time in this case, but this is not documented.

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