Plot selected data of the time-series

Question

NS 2018-3-6

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/386517-plot-selected-data-of-the-time-series

编辑： NS 2018-3-6

Hi,

I have 3D data set x,y and z. z is the 200*17 matrix where each column represents a year (2000-2017). z values are corresponding to the x,y value where x and y are 200*1. Now I want to plot the time-series value of z (2000-2017) for 40-50 value of x and y.

x= [1 2 3 ...40 41 42...49 50....200]; y= [1 2 3 ...40 41 42...49 50....200]; z= [1 2 3..17; 1 2 3...17; ..........till 200]

Thanks in advance

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

KSSV 2018-3-6

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/386517-plot-selected-data-of-the-time-series#answer_308570

在 MATLAB Online 中打开

Extract the respective positions values and plot.

iwant = Z(40:50,:) ; % this picks Z data from 40 to 50.

Now, you can plot iwant.

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

NS 2018-3-6

编辑：NS 2018-3-6

Thanks for the answer. I face another problem now which is if I have the data like that

x=[-75 -74.7649962041000 -74.5299924082000 -74.2949886124000 -74.0599848165000 -73.8249810206000 -73.5899772247000]

y=[ -59.9813461091000 -59.9813461091000 -59.9813461091000 -59.9813461091000 -59.9813461091000 -59.9813461091000 -59.9813461091000]

z is 7*17 matrix. Now if I want to plot time-series value of z for -73.8249810206000 and -59.9813461091000 these x and y value. In addition, How can I find the index value of the element that is closest or equal to -73.8249810206000 and -59.9813461091000 if i put the value like -73.824 -59.981 (only put the 3digits after point) and its extract the values same as -73.8249810206000 and -59.9813461091000.

Thanks

请先登录，再进行评论。