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partitioning a matrix based on another

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Rabeya
Rabeya 2012-5-17
I have two matrices,say, X=[1 2 2; 2 3 3; 3 5 5 ;6 1 2; 3 4 3] and ng=[2;3]. I want to partition X based on ng, i.e.
x1=[1 2 2; 2 3 3], i.e. taking the ng(1) number of rows x2=[3 5 5 ;6 1 2; 3 4 3] , ng(2) number of rows where
X=[x1;x2].
I can do it using a for loop, but is there any efficient way to do this? This is just an example, there can be a larger ng, and also x
  2 个评论
Thomas
Thomas 2012-5-17
do you always have two elements in ng? or can you have more?
Jan
Jan 2012-5-17
I assume, the FOR loop will be the most efficient method - it is required inside MAT2CELL also. If you post your code, we could potentially find improvements.

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2012-5-17
k = mat2cell(X,ng,size(X,2))
[x1,x2] = k{:}

更多回答（1 个）

Honglei Chen
Honglei Chen 2012-5-17
If your matrix can be exactly partitioned, you can use mat2cell. In your problem, X has 5 lines, which cannot be evenly divided by your ng, so I added one line
X=[1 2 2; 2 3 3; 3 5 5 ;6 1 2; 3 4 3; 5 3 2]
y = mat2cell(X,ng(1)*ones(1,size(X,1)/ng(1)),ng(2)*ones(1,size(X,2)/ng(2)))
  2 个评论
Rabeya
Rabeya 2012-5-17
I want to partition it, depending on ng
Honglei Chen
Honglei Chen 2012-5-18
Did you try? Each cell of y holds a partition.

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