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Generate random integers with a condition

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Yesbol
Yesbol 2018-3-7
评论： Yesbol 2018-3-7
Hi all,
I have a matrix A 84x1 (attached). I need to replace ZEROS by randi(3). However, I need to ensure that the number of 1s, 2s or 3s does not exceed 33.
Hope the problem is clear.
Thank you
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Yesbol
Yesbol 2018-3-7
Thanks for your response. Number of 1s, 2s and 3s for each values, i.e. I cannot have more than 33 1s or 33 2s or 33 3s. All zeros are to be replaced by an individual random value
Thanks

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Jan
Jan 2018-3-7
编辑：Jan 2018-3-7
% [EDITED] after the comment:
A = randi([0,5], 84, 1);
z = (A == 0);
nz = sum(z);
ready = false;
while ~ready
A(z) = randi(3, nz, 1);
ready = sum(A==1) < 33 && sum(A==2) < 33 && sum(A==3) < 33;
end
To be sure, add a maximum number of loops. Better stop with an error than run an infinite loop:
count = 0;
while ~ready && count < 1e6
...
count = count + 1;
end
if count == 1e6
error('Cannot find matching values.')
end
A constructive method might be better also: Create a pool with 32 1s, 2s and 3s, and select the elements randomly out of this pool:
pool = repelem(1:3, 32);
index = randperm(numel(pool), nz);
value = pool(index);
Now the vector value must contain less than 33 ones, twos or threes.
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Yesbol
Yesbol 2018-3-7
Thanks for your insights. Creating a pool and selecting the elements randomly out of this pool is a good point

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