Generate random integers with a condition

Hi all,
I have a matrix A 84x1 (attached). I need to replace ZEROS by randi(3). However, I need to ensure that the number of 1s, 2s or 3s does not exceed 33.
Hope the problem is clear.
Thank you

3 个评论

The number of 1s and 2s and 3s together, or for each value? Do you want to replace all zeros by the same random value, or should each zero replaced by an individual random value?
Thanks for your response. Number of 1s, 2s and 3s for each values, i.e. I cannot have more than 33 1s or 33 2s or 33 3s. All zeros are to be replaced by an individual random value
Thanks
I've adjusted the code. See [EDITED]

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 采纳的回答

Jan
Jan 2018-3-7
编辑:Jan 2018-3-7
% [EDITED] after the comment:
A = randi([0,5], 84, 1);
z = (A == 0);
nz = sum(z);
ready = false;
while ~ready
A(z) = randi(3, nz, 1);
ready = sum(A==1) < 33 && sum(A==2) < 33 && sum(A==3) < 33;
end
To be sure, add a maximum number of loops. Better stop with an error than run an infinite loop:
count = 0;
while ~ready && count < 1e6
...
count = count + 1;
end
if count == 1e6
error('Cannot find matching values.')
end
A constructive method might be better also: Create a pool with 32 1s, 2s and 3s, and select the elements randomly out of this pool:
pool = repelem(1:3, 32);
index = randperm(numel(pool), nz);
value = pool(index);
Now the vector value must contain less than 33 ones, twos or threes.

2 个评论

Thanks for your insights. Creating a pool and selecting the elements randomly out of this pool is a good point
Works perfectly! Cheers!

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