getting 'output argument' error when calling function
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I have written this below function :
function [winner_index] = Auction(match_fit,match_index,cbid)
bidmax = 0;
m = match_fit;
w = match_index;
for i = 1:length(m)
bid(i) = cbid*m(i,:);
effectiveBid (i)= bid(i)+randn;
if effectiveBid(i) > bidmax
winner_index = w(i);
bidmax = effectiveBid(i);
end
end
end
Previously when I run this some times it is ok, sometime it was giving the below error " Output argument "winner_index" (and maybe others) not assigned during call to "Auction".
and now I am calling this function inside a loop. It is continuously showing the same error. I don't know why :(
[SL: edited to apply code formatting. Brinta, in the future please use the {}Code button to format your code.]
采纳的回答
Steven Lord
2018-3-22
0 个投票
If effectiveBid(i) > bidmax is not true during any of the iterations, the variable winner_index will never be assigned a value. When the function returns, it tries to take the value of winner_index in the function and return it as the output. But winner_index doesn't exist so MATLAB throws an error.
Define winner_index to a default value before the for loop.
更多回答（1 个）
Jan
2018-3-22
0 个投票
If match_fit is empty or effectiveBid(i) > bidmax is never true, the variable winner_index is not created. The output of randn can be negative.
What do you want to define as output instead in this case?
Note that length(m) is not safe, because it replies the longest dimension. Better use: size(m, 1).
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