locating the relative position of a value in a 2 x matrix

Question

David 2012-5-22

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https://ww2.mathworks.cn/matlabcentral/answers/39037-locating-the-relative-position-of-a-value-in-a-2-x-matrix

I have a 180 by 180 matrix and want to locate the position of the minimum value so I can subsequently reuse the source variables used in the creation of that matrix.

i.e. the minimum valur occurs at row 10 and column 130 but I have not been able to simply return those two numbers.

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Answer 1

Daniel Shub 2012-5-22

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https://ww2.mathworks.cn/matlabcentral/answers/39037-locating-the-relative-position-of-a-value-in-a-2-x-matrix#answer_48614

在 MATLAB Online 中打开

x = randn(180);
[~, I] = min(x(:));
[I, J] = ind2sub(size(x), I);

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Answer 2

David 2012-5-22

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https://ww2.mathworks.cn/matlabcentral/answers/39037-locating-the-relative-position-of-a-value-in-a-2-x-matrix#answer_48621

Thanks - I would not have intuited this from MatLab's limited documentation.

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Answer 3

Daniel Shub 2012-5-22

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https://ww2.mathworks.cn/matlabcentral/answers/39037-locating-the-relative-position-of-a-value-in-a-2-x-matrix#answer_48625

在 MATLAB Online 中打开

From an understanding point, maybe this is better

x = randn(180);
[y, I] = min(x);
[~, J] = min(y);
[I(J), J]

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Answer 4

David 2012-5-22

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https://ww2.mathworks.cn/matlabcentral/answers/39037-locating-the-relative-position-of-a-value-in-a-2-x-matrix#answer_48632

Thanks again - both example solutions extend well beyond the simple MatLab documentation.

My key takeaways from the first solution frame an understanding / confirmation regarding the second. The use of the wild card (:) unlocks some of my road blocks as does the realization that the first index is a linear index that must be converted into row and column designations.