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I have this data :
rank = [18 9 15 17 2 10 13 14 20 5 11 7 8 6 4 19 3 16 1 12 21]
I want to divide data like this
rank a = [18 15 2 13 20 11 8 4 3 1 21] rank b = [9 17 10 14 5 7 6 19 16 12 x]
I want to select x = 18 or is possible select 21 position as x

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Bob Thompson
Bob Thompson 2018-4-13
So you want all even number elements (based on positioning, not value) in one array, and odd number elements in the other?
Muhammad Hafiz
Muhammad Hafiz 2018-4-13
yes Bob, I want all even number in rank a and select rank b into odd number position, I already try this problem but still get some error, please help me to solve this problem

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Bob Thompson
Bob Thompson 2018-4-13

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The sorting is relatively easy with indexing.
rank = [18 9 15 17 2 10 13 14 20 5 11 7 8 6 4 19 3 16 1 12 21]
ranka = rank(1:2:end); % Pull odd numbers (starts at 1)
rankb = rank(2:2:end); % Pull even numbers (starts at 2)
I'm not sure what you mean about the selection of x =

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