slope of a line when intercept is forced to zero

Question

Research 2018-4-18

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/395694-slope-of-a-line-when-intercept-is-forced-to-zero

评论： Research 2018-4-19

Hello, I have simple data set, and wants to calculate the slope when fit line is forced through the origin (0,0). I can do easily in excel. Here is my data

x = [1 2 3 4 5 6]; y = [11 61 111 161 211 261];

using y = mx + c fit equation, I get m = 50, c = -39 and r2 = 1. The fit line does not pass through origin. Now, if I force the line to pass through origin the slope (m) becomes 41 and r2 = 0.96. These are answers from Excel, but how to do this in Matlab? Any help. I tried mldivide function, but no luck.

Thanks again,

Josh

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Rik 2018-4-18

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/395694-slope-of-a-line-when-intercept-is-forced-to-zero#answer_315757

编辑：Rik 2018-4-18

在 MATLAB Online 中打开

x = [1 2 3 4 5 6]; y = [11 61 111 161 211 261];
m=x(:)\y(:);

You can find the doc if you look for mldivide.

edit: thanks for the correction/addition from Star Strider (Converting to an array with (:) always works, while my original solution with a transposition only works if the input is a row vector. I also referred to mrdivide instead of mldivide.)